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3 years ago

BRAINLIEST!!!!!!!!!!!!!

Mathematics

2 answers:

NISA [10]3 years ago

7 0

Answer:
C

Explanation:
As it states in the instructions, you need to go back 4 times and go up 4 times.
If you subtract the original coordinates with x by 4 you should get the correct answer.
For y, it’ll be the same.

Stells [14]3 years ago

6 0

I think B

Step-by-step explanation:

Correct me if I'm wrong

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There are 30 singers in a show. The ratio of singers to dancers is 5:6. How many dancers are there?

Tamiku [17]

Answer: 32 dancers

Step-by-step explanation:

I drew a chart and on the side with the singers you count by 5's until u get to 30. On the dancers side of the chart you count by 6's until it lines up with 30 on the singers side.

5 0

3 years ago

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At the start of the week a bookshop had science and art books in the ratio 2:5. By the end of the week, 20% of each type of book

Anastaziya [24]

Let there be 2x science and 5x art books
science books sold = 2x × 0.2 = 0.4x 
science books unsold = 2x – 0.4x = 1.6x 

art books sold = 5x × 0.2 = x 
art books unsold = 5x – x = 4x 

total books unsold = 1.6x + 4x = 5.6x 
5.6x = 2240 
x = 400 

2x science = 800 
and 5x art books = 2000

5 0

4 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

Help me with this math equation.

Stells [14]

8/2•m or to simplify 4m

7 0

3 years ago

Add: 8p + (-6p6 + 5)

Alika [10]

Answer:

$-6p^6 +8p + 5$

Step-by-step explanation:

$8p + -6p^6 + 5$

$-6p^6 +8p + 5$

6 0

3 years ago

Read 2 more answers