Answer:
x=5
Step-by-step explanation:
You can use the 30-60-90 rule or trigonometry to solve this.
<u>The 30-60-90 rules states...</u>
- the hypotenuse is 2x
- The long leg is
![x\sqrt{3}](https://tex.z-dn.net/?f=x%5Csqrt%7B3%7D)
- the short leg is x
Ex: short leg is 7 which means the long leg is
and the hypotenuse is 14
Therefore if the hypotenuse is 10 then x (short leg) should be 5
<u>Trigonometry also proves this...</u>
<u>Sine</u>
<u>Opposite</u>
<u>Hypotenuse</u>
Cosine
Adjacent
Hypotenuse
Tangent
Opposite
Adjacent
We will use SINE since we are trying to find the leg opposite to the 30 degree angle and the hypotenuse is already given (10)
![sin30=\frac{x}{10}\\sin30*10=x\\x=5](https://tex.z-dn.net/?f=sin30%3D%5Cfrac%7Bx%7D%7B10%7D%5C%5Csin30%2A10%3Dx%5C%5Cx%3D5)
(Use a calculator for this)
Chad could've made a mistake and drew an acute triangle, thats a triangle that has 2 sides thats 3 inches and 1 side dats 2 inches
Answer:
a
Step-by-step explanation:
something are very complex
Answer:
C
Step-by-step explanation:
Domain of the function is the whole R
Answer: Choice D) 5.9
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We'll be using the tangent rule two times to find the lengths of BD and BC, which we'll subtract to compute the length of CD. Make sure your calculator is in degree mode.
---------
Focus on triangle ABC for now (ignore point D)
For reference angle A:
AB = adjacent = 85
BC = opposite = unknown = x
tan(angle) = opposite/adjacent
tan(A) = BC/AB
tan(28) = x/85
x = 85*tan(28)
x = 45.1953
---------
Now focus on triangle ABD (ignore point C)
For reference angle A:
AB = adjacent = 85
BD = opposite = unknown = y
tan(angle) = opposite/adjacent
tan(A) = BD/AB
tan(31) = y/85
y = 85*tan(31)
y = 51.0732
---------
Subtract x and y (large-small)
y-x = 51.0731-45.1953 = 5.8778
this rounds to 5.9