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svet-max [94.6K]
2 years ago
9

Help! How to factorise= x²-5x+6?!!!!!!

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
3 0

Answer:

(x − 2)(x − 3)

Step-by-step explanation:

x² - 5x + 6

(x − 2)(x − 3)

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Solve this equation <br> 16x^2-81=0
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Answer:

The answer should be C

Step-by-step explanation:

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You are downloading a song. The percent y(in decimal form) of megabytes remaining to download after x seconds is y=-0.1x+1.
igomit [66]


I would make the equation have both of your variables on the same side:

0.1x+y=1

Then I would use the cover-up method and say that

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*Cover-Up Method: If you were finding the X-intercept, you would just ignore the y variable and divide your whole number by x.

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Vice Versa with finding the Y-intercept

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4 ? 10<br> 9 22 <br><br> Do these two ratios form a proportion
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What are the zeros of the polynomial function? <br><br> F(x)= x^2 +12x
Pavel [41]

Answer:

x = 0 and x = -12 are the two zeroes

Step-by-step explanation:

"Zeroes" of a function are also called the solutions, roots or x intercepts.

The zeroes are the numbers that give the function a values of 0, so find what value for 'x' yields F(x) = 0 as a result.

With quadratic equations (equations with x² as the largest exponent), you factor the equation.  

Step 1: Set the equation equal to zero

  x² + 12x = 0

 Depending on the equation, there are several methods you can use to factor, for this one we can factor out an 'x' since both terms have an 'x' in them.  We get...

  x(x + 12) = 0      

So now, using the "zero product property" which means that if two things are multiplied together, and the result is zero, then either the first term is zero, the second term is zero, or they are both zero.  So we set each term equal to zero and solve.

So

either    x = 0     or        x + 12 = 0

Solve each for x to get your two anwers.

x= 0 is already solved, so 0 is our first zero

Now solve

x + 12 = 0  

  x = -12             (subtract 12 from both sides to isolate x)

 

8 0
3 years ago
Assume that f(x)=ln(1+x) is the given function and that Pn represents the nth Taylor Polynomial centered at x=0. Find the least
WINSTONCH [101]

Answer:

the least integer for n is 2

Step-by-step explanation:

We are given;

f(x) = ln(1+x)

centered at x=0

Pn(0.2)

Error < 0.01

We will use the format;

[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01

So;

f(x) = ln(1+x)

First derivative: f'(x) = 1/(x + 1) < 0! = 1

2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1

3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2

4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6

This follows that;

Max|f^(n+1) (c)| < n!

Thus, error is;

(n!/(n + 1)!) × 0.2^(n + 1) < 0.01

This gives;

(1/(n + 1)) × 0.2^(n + 1) < 0.01

Let's try n = 1

(1/(1 + 1)) × 0.2^(1 + 1) = 0.02

This is greater than 0.01 and so it will not work.

Let's try n = 2

(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267

This is less than 0.01.

So,the least integer for n is 2

7 0
4 years ago
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