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GaryK [48]
3 years ago
14

Find the value of arc s

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

≈ 38.64 units

Step-by-step explanation:

The length of arc s is calculated as

circumference of circle × fraction of circle

The central angle subtended by arc s is 360° - 114° = 246° then

arc s = 2πr × \frac{246}{360}

        = 2π × 9 × \frac{41}{60}

        = 18π × \frac{41}{60}

        ≈ 38.64 ( to 2 dec. places )

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Let P(1,2,1), Q(1,0,-1), R(2,2,0) be the vertices of a parallelogram with adjacent sides PQ and PR. Find the other vertex S.
ladessa [460]

Given:

The vertices of a parallelogram are P(1,2,1), Q(1,0,-1), R(2,2,0).

PQ and PR are the adjacent sides of the parallelogram.

To find:

The coordinates of vertex S.

Solution:

We know that, the diagonals of a parallelogram bisect each other.

Let the coordinates of the vertex S are (a,b,c).

In the given parallelogram PS and QR are the diagonals. It means their midpoints are same.

\left(\dfrac{1+a}{2},\dfrac{2+b}{2},\dfrac{1+c}{2}\right)=\left(\dfrac{1+2}{2},\dfrac{0+2}{2},\dfrac{-1+0}{2}\right)

\left(\dfrac{1+a}{2},\dfrac{2+b}{2},\dfrac{1+c}{2}\right)=\left(\dfrac{3}{2},\dfrac{2}{2},\dfrac{-1}{2}\right)

On comparing both sides, we get

\dfrac{1+a}{2}=\dfrac{3}{2}

1+a=3

a=3-1

a=2

Similarly,

\dfrac{2+b}{2}=\dfrac{2}{2}

2+b=2

b=2-2

b=0

And,

\dfrac{1+c}{2}=\dfrac{-1}{2}

1+c=-1

c=-1-1

c=-2

Hence, the coordinates of vertex S are (2,0,-2).

4 0
3 years ago
Please help ill give brainliest
dimulka [17.4K]

Did you know 1+1=3

Step-by-step explanation:

4 0
3 years ago
You can always _____ two similar triangles so that they become congruent.
storchak [24]

Answer:

<em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>h</em><em>a</em><em>v</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>b</em><em>e</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>l</em><em>.</em>

Step-by-step explanation:

you can always equal two similar triangles so that they become congruent.

In the ratio of the length of their sides is equal to one, they are congruent. So, all congruent triangles have to be similar but all similar triangles need not be congruent......the ratio of corresponding sides,AB/A'B'=BC/B'C'=CA/C'A'. If the two triangles are congruent AB/A'B'=BC/B'C'=CA/C'A'=1

I am glad to help you!!!!

5 0
3 years ago
What’s the square root of 3
belka [17]
According to my calculations. The answer to this question is 89
5 0
4 years ago
Read 2 more answers
Please help me on this question thanks ! I will mark you brainliest
igomit [66]

Answer:

3x+2°=65° (vert opp angles)

3x=65°-2°

=63°

x=63÷3

=21

7 0
3 years ago
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