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Lana71 [14]
3 years ago
6

A student took a total of 4 tests over the course of 8 weeks. How many weeks of school will the student attend to take a total o

f 20 tests?
Mathematics
1 answer:
Julli [10]3 years ago
3 0

Answer:

4/8 = 20/x

20 x 8 = 160

160 ÷ 4 = 40

the student will attend 40 weeks of school

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(79,35+7,32) × 42,2-9543​
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Answer:

42(79,42,32)

Step-by-step explanation:

I got the solution by using  the  Trigonometric Identities. If somebody else could do a step by step explanation that would be great.  

3 0
3 years ago
A study of class attendance and grades among first-year students at a state university showed that, in general, students who mis
ratelena [41]

Answer:

the numerical value of the correlation between percent of classes attended and grade index is r = 0.4

Step-by-step explanation:

Given the data in the question;

we know that;

the coefficient of determination is r²

while the correlation coefficient is defined as r = √(r²)

The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.

Now, given that class attendance explained 16% of the variation in grade index among the students.

so

coefficient of determination is r² = 16%

The correlation coefficient between percent of classes attended and grade index will be;

r = √(r²)

r = √( 16% )

r = √( 0.16 )

r = 0.4  

Therefore,  the numerical value of the correlation between percent of classes attended and grade index is r = 0.4

3 0
3 years ago
When actual trials are difficult to conduct, you can find experimental probabilities using this model of one or more events.
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6 0
2 years ago
Determine the ordered pair that satisfies the equation, 6x - 3y = 5.
Kazeer [188]

Given the equation 6x-3y=5.

Check all options:

A. \left(9,\dfrac{16}{3}\right), this means that x=9, y=\dfrac{16}{3}. Substitute these numbers into the left side of the equation equation:

6\cdot 9-3\cdot \dfrac{16}{3}=54-16=38\neq 5.

This option is false.

B.  \left(6,-3\right), this means that x=6, y=-3. Substitute these numbers into the left side of the equation equation:

6\cdot 6-3\cdot (-3)=36+9=45\neq 5.

This option is false.

C.  \left(1,-\dfrac{11}{3}\right), this means that x=1, y=-\dfrac{11}{3}. Substitute these numbers into the left side of the equation equation:

6\cdot 1-3\cdot \left(-\dfrac{11}{3}\right)=6+11=17\neq 5.

This option is false.

D.  \left(-2,-\dfrac{17}{3}\right),  this means that x=-2, y=-\dfrac{17}{3}. Substitute these numbers into the left side of the equation equation:

6\cdot (-2)-3\cdot \left(-\dfrac{17}{3}\right)=-12+17=5.

This option is true.

Answer: correct choice is D.

3 0
3 years ago
Read 2 more answers
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