1,248 divided by 4= 312
your welcome
:))
for f(x) = -2(x-4)2+2 - set equation to y = -2(x-4)2+2, solve x-4=0, x = 4
axis of symmetry is x = 4
for g(x) = 5x2-10x+7, set equation to y = 5x2-10x+7, solve the square: 5x2 becomes 5(x-1)2 solve x-1 = 0, x = 1
axis of symmetry is x=1
for H(x) what x value would be the centerline so that the graph symmetry is the same on both sides? looking at the graph the top of the arc is on -2
so axis of symmetry is x = -2
Is there anyway you could reupload the picture or write it on paper so we can see the full question ? (:
