Answer: B:The drought decreased the grass and vegetation on the ground, leaving only vegetation on shrubs and trees above the ground. Natural selection selected for the tortoises with the domed shells and hoods.
Explanation:
<h2>Answer </h2>
DNA are found in the cells of all living organisms
<u>Explanation</u>
DNA is a complex molecule consisting of many components which are passed from parent organisms to their offsprings during the process of reproduction. The DNA contains instruction needed for an organism to develop survive and reproduce. DNA is deoxyribonucleic acid and is contained in your body's cells. From microscopic view they are double, large cable of particles termed as nucleotides. This show the cell what proteins to produce in the living organism. Hence, all living things have DNA within their cells.
Answer:
The different possible genotypes are AA, AO, BB, BO, AB, and OO. These are derived according to the A, B and O blood group model.
The table is given below:
Blood Type Genotype
Blood Type A Genotypes AA or AO
Blood Type B Genotypes BB or BO
Blood Type AB Genotype AB
Blood Type O Genotype OO
The alleles A and B exhibit a greater dominance than O. This is the reason why the Parent of Blood type A will form the Genotype AO.
Answer:
eukaryotic cells
There are two basic types of cells, prokaryotic cells and eukaryotic cells. The main difference between eukaryotic and prokaryotic cells is that eukaryotic cells have a nucleus. The nucleus is where cells store their DNA, which is the genetic material. The nucleus is surrounded by a membrane
Explanation:
Answer:
The answer is 83.38%.
Explanation:
The probability of young children having blood levels that impair their neurological development is given as 60% in the question. To find the probability of at least 5 children out of 10 in a sample having said blood levels, we need to use the binomial probability.
n represents the total number of children in the sample so n = 10 and p is the probability of the children having blood levels causing the problem which is 60% so p = 0.6.
We want the probability of it being observed for 5 or more children and that is 
. If we subtract the 
from 1, which is the probability of not observing the condition in 5 or more children, we will have the .
which are the probability range in the function, the sample size and the probability of observing the condition respectively.
The result is 1 - 0.1662 = 0.8338 which means that the probability that is asked is 83.38%.
I hope this answer helps.
