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ioda
3 years ago
15

I really need help with these 4 questions, whoever answers CORRECTLY gets brainliest.

Mathematics
2 answers:
Citrus2011 [14]3 years ago
7 0

B
B
D
A
Explanation, I have a 128% in math rn…
Ann [662]3 years ago
7 0
<h3>1. Which ordered pair is a solution of the equation y = x - 4?</h3>

[ Option A ]

(2,6)

y = x - 4

6 = 2 - 4

6 = -2 ❎

[ Option B]

(6,2)

y = x - 4

2 = 6 - 4

2 = 2 ✔️

[Option C ]

(-2,6)

y = x - 4

6 = -2 - 4

6 = -6 ❎

[ Option D ]

(-6,2)

y = x - 4

2 = -6 - 4

3 = -10 ❎

<h3>2. Which value is a solution of the equation 3 - 2x = -5?</h3>

A. 2

B. 4✔️

C. -2

D. 1/5

<u>Step by step explanation :</u>

3 - 2x = -5

3 + 5 = 2x

8 = 2x

8/2 = x

<u>4 = </u><u>x</u>

<h3>3. Which ordered pair is a solution of the equation y = 5x?</h3>

A. (-2,10)

B. (-5,25)

C. (-3,15)

D. (-2,-10)✔️

<u>Step by step explanation :</u>

y = 5x

y/x = 5

(-10)/(-2) = 5

<h3>4. Which ordered pair is a solution of the equation y = -9x + 4?</h3>

A. (10,-86)

y = -9x + 4

-86 = -9(10) + 4

-86 = -90 + 4

-86 = -86 ✔️

B. (-4,-58)

y = -9x + 4

-58 = -9(-4) + 4

-58 = 36 + 4

-58 = 40 ❎

C. (6,-41)

y = -9x + 4

-41 = -9(6) + 4

-41 = -54 + 4

-41 = -50 ❎

D. (-6,57)

y = -9x + 4

-57 = -9(-6) + 4

-57 = 54 + 4

-57 = 58❎

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WILL UPVOTE EVERY ANSWER! MULTIPLE CHOICE QUESTIONS!
Setler [38]
Do you mean ^2? cause if so... B don't really need crit points to solve, the parabola has a positive slope before x =2 
8 0
3 years ago
given the equation y-5=5x determine whether the points (2,12) and (-2,-5) are a solution on the graph
Flura [38]
(x,y)
sub points to see if we get true statemtn

(2,12)
x=2 and y=12

12-5=5(2)
7=10
false
no, (2,12) is not a point


(-2,-5)
x=-2
y=-5

-5-5=5(-2)
-10=-10
true
(-2,-5) is a soltuion

(-2,-5) is the only solution given that works
6 0
3 years ago
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
How to do a histogram
aleksklad [387]

Answer:histogram is like bar graph only but point is that in bar garph be used to leave some space when we are drawing the bar graph in graph but when we are making the histogram we are not going to leave this place

8 0
3 years ago
Help huryyyyyyyyyyyyy
zhuklara [117]

Answer: 4

Step-by-step explanation:

Because %s can be expressed as fractions over 100, because 90 is 70% of x, 70% is 70% of 100.  Thus, 90/x = 70/100.

<em>Hope it helps <3</em>

8 0
3 years ago
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