Let f= {(-5,1).( - 4,0).(0,6)} Find f(0) f(0)=
1 answer:
<u>Given</u>:
It is given that the coordinates of the function are
We need to determine the value of f(0)
<u>Value of f(0):</u>
The value of f(0) is the value of the function when the input is 0.
We need to determine the value of f(0) when the input is x = 0
Thus, from the coordinates of the function , it is obvious that the input value of the function is x = 0 , then the value of the function f(0) = 6.
Thus, when the input value x = 0, the output is f(0) = 6.
Therefore, the value of f(0) = 6.
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Answer:
<h2>f(0) = -4</h2>Step-by-step explanation:
You can use the definition:
Then if
we have
Then the derivative is
I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is
and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).
Use the point-slope formula to get the equation of the tangent line:
<em>y</em> - (-2) = 3 (<em>x</em> - 0)
<em>y</em> + 2 = 3<em>x</em>
<em>y</em> = 3<em>x</em> - 2