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OLga [1]
3 years ago
8

2,776,714 rounded to the greatest place value is?How many zeros are in the rounded number?The estimated speed of light using a p

ower of 10 is? *
Mathematics
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

One third of 24

Step-by-step explanation:

because 3 is a whole number smaller than 4 so the answer would be 3/24 not 4/16.  

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Can you solve 2|x+4|<-10
Umnica [9.8K]

Answer: no solution

Step-by-step explanation: the answer will be negative

7 0
3 years ago
Tavon has a gift card for $70 that loses $3 for each​ 30-day period it is not used. He has another gift card for $ 60 that loses
vladimir2022 [97]

Hello,


Your answer would be: 55


<u><em>My work:</em></u>

For this problem all you have to do is keeping subtracting 3 until you get a matching number in which I got 55.


Hope this helps!


Brainliest!?!


Have a great day:)


~Rendorforestmusic

5 0
3 years ago
Help plz it’s due today
Temka [501]
There’s no picture u should repost
5 0
3 years ago
Q20-23 with steps pls
just olya [345]

20: Let x be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30

Rearrange the left hand side as

\dfrac{4x-3x}{24}=30

And multiply both sides by 24 to get

x=720

21: Let M and J be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

M=3J+11

If they both get 9 more marbles, Mike will have M+9 marbles, and Judy will have J+9 marbles. So, we have

M+J+18=93 \iff M+J=75 \iff M=75-J

Plug this value in the first equation and we have

75-J=3J+11 \iff 4J=64 \iff J=16

And we deduce

M=16\cdot 3 + 11=59

So, the difference is  

M-J=59-16=43

22: Let x,y,z be the number of $10, $20 and $50 coupon, respectively. We're given:

\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}&#10;We can write the third equation by substituting the expressions for x and z:&#10;[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38

Rearrange as follows:

(2y+3)+y+\left(\dfrac{1}{2}y\right)=38 \iff \dfrac{7}{2}y=35 \iff 7y=70 \iff y=10

And now we can deduce the number of the other coupons:

x=2\cdot 10+3=23,\quad z=\dfrac{1}{2}\cdot 10=5

So, the total value is

23\cdot 10+10\cdot 20+5\cdot 50=230+200+100=530

23:  a) In order to find the first three terms of the sequence, you just need to plug n=1,2,3:

a_1=4\cdot 1+3=7,\quad a_2=4\cdot 2+3=11,\quad a_3=4\cdot 3+3=15

b) We have

a_r = 4r+3=71 \iff 4r=68 \iff r=\dfrac{68}{4}=17

c) 105 is a term of the sequence if and only if there exists an integer k such that

a_k=4k+3=105 \iff 4k = 102 \iff k=\dfrac{102}{4}=25.5

So, 105 is not a term of the sequence.

8 0
4 years ago
28 kg of bananas cost $56. How much<br> would 36 kg cost?
zhenek [66]

Answer:

$72

Step-by-step explanation:

$56.00÷28=2. $36.00×2=$72.00

Hope this helps :)

5 0
3 years ago
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