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3 years ago

Which part of this graph shows a nonlinear relationship? Depth of water 2 Time O A. 3 OB. 4 O C. 1 D. 2

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

Answer:

Which part of this graph shows a nonlinear relationship? Depth of water 2 3. Time A. 2. B. 1. C. 3. O D. 4. 1

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Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.2 chocolate chips per cookie and a sta

Allisa [31]

Answer:

Percentile 5

$z=-1.64$

And if we solve for a we got

$a=24.2 -1.64*2.6=19.94$

Percentile 95

$z=1.64$

And if we solve for a we got

$a=24.2 +1.64*2.6=28.46$

Step-by-step explanation:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(24.2,2.6)$

Where $\mu=24.2$ and $\sigma=2.6$

We want to find the percentiles 5 and 95 for this case.

Percentile 5

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.95$ (a)

$P(X$ (b)

We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05

Using this condition we got:

$P(X$

$P(z$

Replacing we got:

$z=-1.64$

And if we solve for a we got

$a=24.2 -1.64*2.6=19.94$

Percentile 95

$z=1.64$

And if we solve for a we got

$a=24.2 +1.64*2.6=28.46$

4 0

3 years ago

How many solutions does the following equation have? -4(+5) = -4- 20

Rus_ich [418]

Answer:

Step-by-step explanation:

Try looking at it in 2 ways- left side and right side. On the left side we have -4*5, which equals -20. On the right we have -4-20, which equals -24. so then when we add it all together (not literally) we get -20=-24. Since -20 and -24 obviously do not equal eachother, there is no solution.

4 0

3 years ago

I need to know how to solve this

Greeley [361]

Vertical angles are congruent, so
107=3x-4
3x=111
x=111/3=37°

8 0

3 years ago

Read 2 more answers

What value of x makes the equation true? A.1 B.-5 C.-1 D.7

Temka [501]

I THINK THE ANSWER IS D.

5 0