Answer:
A(n) = 100(1.1)^n
Step-by-step explanation:
Given that :
Account balance = A(n)
Compound interest paid = 10%
We need to obtain the initial amount deposited, that is A(n), when n = 0
In year, n = 1
Account balance, A(n) = $110
Let initial deposit = P
Hence,
Compound interest relation should be ;
A(n) = P(1 + r)^n
Plugging in our values
110 = P(1 + 0.1)^1
110 / P = 1.1^1
110/P = 1.1
110 = 1.1P
P = 110 / 1.1
P = 100
Hence, we can define the amount paid inn n years by substuting the value of P into the compound interest formula :
A(n) = 100(1 + 0.1)^n
A(n) = 100(1.1)^n
Where are the triangles so I can compare to find the triangle congruence?
13+13=26
9+9=18
18+26=44
Hope this helps :)
Answer:
16n^2+40n+25
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
Let's represent this with an equation, where x is the first number. The next number must be x+2, because it has to be even, not x+1, and the rest continue the same way:
x+(x+2)+(x+4)+(x+6)+(x+8) = 100
Solve for x.
5x+20 = 100
5x = 80
<u>x = 16</u>
