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Katen [24]
3 years ago
12

Please please help me I will give you brainless please

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

f(x) = 2x - 1 \\ g(x) = 3x \\ h(x) =  {x}^{2} + 1 \\ f( g(x)) = 2(3x) - 1 = 6x - 1 \\ f( g( - 3)) = 6( - 3) - 1 =  - 19 \\ h(f(x)) =  {(2x - 1)}^{2}  + 1 \\ h(f(0)) =  {(2(0) - 1)}^{2}  + 1 \\ h(f(0)) = 2

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4 years ago
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