Question

So, I have a math problem, the problem is,16x^0+2x^2*y^-1,How do I solve if x = 2 and y = 4?

Answer 1

Answer:

Given x = 2 and y =4

so 16$x^{0}$+2$x^{2}$$y^{-1}$

= 16*$2^{0}$ + 2*$2^{2}$*$4^{-1}$

= 16 + (2*4)/4

=16 + 8/2

16 + 2

=18

Step-by-step explanation: