Can someone please help me out
1 answer:
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Answer:
c. binomial distribution with n = 5 and p = 1/33.
Step-by-step explanation:
For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability of a birth resulting in a defect is independent of other births. So we use the binomial probability distrbution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The proportion of American births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).
This means that the probability of a birth resulting in a defect is
A local hospital randomly selects five births.
This means that
So the correct answer is:
c. binomial distribution with n = 5 and p = 1/33.