Y=x-8----equation 1
2x+3y=1------equation 2
2x+3(x-8)
2x+3x-24=0
5x=24
x=24/5
x=~5
substitute for X in equation 1
y=5-8
y=-3
(5,-3)
1. x=2
2. X=100
3. X=100
4.-1
8+g
that is the expressioin!!
Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:

where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)

Time to clean up the inside of the ( ).


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2nd Problem:
Compounded continuously problems use base as e.

P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.