The answer is greenhouse effect
1. Interphase is an important and the longest phase of the cell cycle during which the cell prepares for division by coping its DNA. It is metabolic phase of the cell, in which the cell grows, obtains nutrients and metabolizes them. There are three stages of interphase: G1 (the cell growth), S (replication of DNA, chromosomes are copied) and G2 (preparation for division). Without this phase, genetic material wouldn’t be ready for the process of meiosis and haploid gametes couldn’t be created.
2. Homologous chromosomes are the similar but not totally identical chromosome pairs that an organism receives from its two parents. During the prophase I of meiosis they pair up: each chromosome aligns with its homologue partner via link-chiasmata ( the two match up at corresponding positions). Those homologue pairs separate during a first stage of cell division (meiosis I-reduction of chromosomes number, from diploid to haploid), while sister chromatids separate during a second stage (meiosis II).
3. Crossing over is a process in which homologous chromosomes trade their parts. Crossing over is process of genetic recombination where DNA is cut and then repaired. Cut and repair of homologous chromosomes allow them to exchange some of their genetic information. As a consequence of crossing over, new arrangement of maternal and paternal alleles on the same chromosome is achieved. It is the way to create varations.
4. During the metaphase I, homologue pairs are lined up comparing to metaphase II where individual chromosomes are lined up. It is because during the meiosis I homologue pairs separate and chromosome number reduce from diploid to haploid. On the other hand, during the meiosis II, sister chromatids separate.
5. Nondisjunction is the consequence of cell division, where there is no properly separation. There are different forms of nondisjunction:
• failure of a pair of homologous chromosomes to separate in meiosis I,
• failure of sister chromatids to separate during meiosis II.
After nondisjunction, resulting daughter cells are with abnormal chromosome numbers -aneuploidy.
Image is not avilable fo rthe question. The image is attached below:
The phylogenetic tree shown here displays the major clades of chordates.
Which statements about the phylogenetic tree are true?
A) Organism (c) is a common ancestor of lampreys and lungfishes.
B) Birds and ray-finned fishes have a notochord and jaws.
C) Lancelets and coelacanths are more closely related than are chimaeras and coelacanths.
D) Mammals and turtles are more closely related than are lungfishes and sharks.
E) Rays and frogs have vertebrae.
F) Descendants of organism (d) have limbs with digits.
G) Hagfishes, lungfishes, and frogs have lobed fins.
H) Organism (a) is a common ancestor of all chordates.
Answer:
B, D, F, E, H.
Explanation:
A phylogenetic tree is a diagram representing evolutionary relations between species. Phylogenetic trees are not conclusive evidence nor theories. In a phylogenetic tree the pattern of branching illustrates how organisms or other groups developed from a set of similar ancestors.
Some of the examples of phylogenetic tree are as following:
- A notochord and jaws includes in birds and ray-finned fishes.
- Mammals and tortoises are closer to one another than lungfish and sharks are.
- Organic Descendants (d) have wings.
- Rays and frogs are columned vertebrally.
- A shared ancestor of all chordates is the organism (a).
Hence, the true options are B, D, F, E, H.
"glucose" (and if available "water" and "mitochondria") is needed for both anaerobic and aerobic respiration!
Answer:
adhesive
Explanation:
the water sticks to the glass because of surface tension
