5^(x² - 2x) = 1
5^(x²) - 5^(2x) = 1
5^x² - 5²x = 1
Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
Answer:
7.(1,0) and (-4,0)
8. (-3,0) and (-2,0)
Step-by-step explanation:
7.
When the function is equal to zero, we are looking for the zeros, or the x intercepts
Where it crosses the x axis are 1 and -4
(1,0) and (-4,0)
8. When the function is equal to zero, we are looking for the zeros, or the x intercepts
Where it crosses the x axis are -3 and -2
(-3,0) and (-2,0)