Answer:
-1
Step-by-step explanation:
can be soled by substitution remember BEDMAS
can also be written like this
((-2)-2*(-0.5))^3
<h3 /><h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3><h3>Required Solution :</h3>
Let the first even number be 'x' & the second even number be (x + 2)
<u>According to the Question</u>,
⇒x + (x + 2) = 34
⇒x + x + 2 = 34
⇒2x + 2 = 34
⇒2x = 34 - 2
⇒2x = 32
⇒x = 32/2
⇒x = 16
⇒First even number = x = 16
⇒Second even number = (x + 2) = 16 + 2 = 18
<u>∴</u><u> </u><u>The t</u><u>wo consecutive even n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>s</u><u> are 16 & 18</u> ...!
<h3>Verefication : </h3>
As, In our Question it was given that "The sum of two consecutive even numbers is thirty-four". So, as we got our two consecutive even numbers as 16 & 18 ... By this, we can say that these both even numbers should be equals to 34, i.e., 16 + 18 = 34. Hence, The equation which we formed is correct ...!
<h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
Answer:
Step-by-step explanation:
<h3>AP given</h3>
<h3>To find</h3>
<h3>Solution</h3>
Common difference
<u>Difference of first two</u>
- d = (a -b) - (a + b) = -2b
<u>Difference of second two</u>
<u>Difference of last two</u>
<u>Now comparing d:</u>
- -2b = ab - (a - b)
- ab - a = - 3b
- a(1 - b) = 3b
- a = 3b/(1 - b)
and
- a/b - ab = -2b
- a(1/b - b) = -2b
- a = 2b²/(b² - 1)
<u>Eliminating a:</u>
- 2b²/(b² - 1) = 3b/(1 - b)
- 2b/(b+1) = -3
- 2b = -3b - 3
- 5b = - 3
- b = -3/5
<u>Finding a:</u>
- a = 3b/(1 - b) =
- 3*(-3/5) *1/(1 - (-3/5)) =
- -9/5*5/8 =
- -9/8
<u>So the first term is:</u>
- a + b = -3/5 - 9/8 = -24/40 - 45/40 = - 69/40
<u>Common difference:</u>
<u>The 6th term:</u>
- a₆ = a₁ + 5d =
- -69/40 + 5*6/5 =
- -69/40 + 240/40 =
- 171/40 = 4 11/40
Our goal is to get y by itself
We will first add 3x to both sides to get
-5y = 3x - 15
We will then divide both sides by -5 to get y by itself which becomes
y = -3/5x + 3
Answer:
Dan paid $80 for his luggage
Step-by-step explanation:
$400
-$320
= $80
Jake wants to go to a lil uzi vert concert. A lil uzi vert concert ticket cost $320. The backstage pass is only $400, so Jake pays for that instead. He later figured out that he wanted to lose 50 pounds before the concert in 6 months and for every time he goes to the gym he has to pay $10 he only goes to the gym 8 times and his bank account has $500 on it. How much money did he have left over after going to the gym 8 times? - PS don't worry about this question its just a fake scenario i made for the second part of your question hope this helps!!!
