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3 years ago

3x^2 - 12x ÷ x-4 what is this simplified

Mathematics

2 answers:

Andreyy893 years ago

8 0

3x^2−16 I think that's the answer. Hope that helps!

Alexxandr [17]3 years ago

5 0

Honestly you should simplify it by doing Gemdas. Grouping symbles, exponents,multiplication,division,subtraction. Honestly i think if you do it right one of the steps should give you an answer

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NNADVOKAT [17]

Answer:

x=14.5

If the answer is 14.5 move to J.

Explanation:

The sum of adjacent angles is 180

(8x-11)+(4x+17)=180

12x+6=180

12x=174

x=14.5

3 0

3 years ago

A=e(b-c)-d B=6, c=3,d=-4, e=-2 Find the value please

MissTica

Answer:

A=e(b-c)-d

A=-2(6-3)-4

A=-12+6-4

A=-6-4

A=-10

3 0

2 years ago

Use the information given to enter an equation in standard form. (−1, 1) and (0, 2) .

AVprozaik [17]

First find the slope:

m = ( 2 - 1 ) / ( 0 - (-1) ) = 1 / 1 = 1

Set up slope-intercept form:

y = 1·x +2

Now move x and y to the left and leave 2 on the right:

-x + y = 2

This is also equivalent to x - y = -2, so that just depends if you want your x coefficient to be positive or negative.

5 0

3 years ago

Read 2 more answers

PLEASE HELP WILL GIVE THANKS AND FIVE STARS IF RIGHT ANSWER

Vika [28.1K]

(x+4)^2 / 9 - (y+3)^2 / 16 = 1

a^2 = 16 and b^2 = 9

a = +4 and -4

b = +3 and -3

Center is (-4, -3)

Vertices is (-4 + a, -3) and (-4 - a, -3)

Vertices is (-1, -3) and (-7, -3)

8 0

3 years ago

Suppose the coordinate of a is 0, ar = 5, and at =7. What are the possible coordinates of the midpoint of rt ?

77julia77 [94]

Here 'a' corresponds to 0.

Now there are two possibilities for 'r' & 't'

Case 1.

They are on the same side to the right of 'a'

In that case 'r' corresponds to 5 & 't' corresponds to 7.

The midpoint of 'r' and 't' shall be $\frac{5+7}{2} =6$

Case 2.

Both are on the left of 'a'.

In that case 'r' corresponds to -5 & 't' corresponds to -7

The midpoint shall be $\frac{-7-5}{2} =-6$

Case 3.

'r' in on the right of 'a' and 't' is on the left of 'a'

So 'r' corresponds to 5 and 't' corresponds to -7

The midpoint shall be $\frac{-7+5}{2}=-1$

Case 4.

'r' is on the left of 'a' & 't' is on the right of 'a'.

'r' corresponds to -5 & 't' corresponds to 7

The midpoint shall be $\frac{-5+7}{2}=1$

The possible coordinates of the midpoints of rt are 6, -6, 1, -1.

4 0

4 years ago