Answer:
- The p<u>harngotympanic tube </u>is in the <u>middle ear</u>.
- The<u> helicotrema</u> is in the <u>inner ear.</u>
- The <u>stapedius</u> is in the <u>middle ear</u>.
Explanation:
The ear has three main parts, the outer part, the middle part, and the inner part. The outer part of the ear starts in the auricle, then it continues with the auditory canal, and it finishes with the eardrum. Then we have the middle ear that is separated from the outer one with the eardrum. In this section, it is the pharngotympanic tube, also known as the Eustachian tube. It is a tube that connects the inner ear with the pharynx to regulate internal pressure.
The inner ear has the bony labyrinth and the membranous labyrinth. In this part of the ear, the mechanical signals are transformed into electrical signals. The bony labyrinth has the cochlea, the vestibule, and the semicircular canals. The helicotrema is in the cochlea, and it connects the tympanic duct with the vestibular duct.
The stapedius is a muscle located in the middle ear. Its insertion is in the stapes, a small bone that moves with the vibrations that come from the eardrum to the malleus and the stapes. The stapedius' function is to protect our hearing by reducing the vibrations that enter this part of the ear.
Kindly see answers below:
1. The answer is Genotypic. Evolution refers to the genetic change in a population over the time.
2. The answer is No. Jumping Jack Flash's speed is a result of diet and exercise, not by a genetic trait.
3. Natural Selection is the process in which an organism is well adapted to the environment.
Answer:
B) 2pq
Explanation:
Hardy-Weinberg equilibrium refers to a model which explains the effect of evolution on the gene pool.
The model is based on the assumptions that if no evolutionary force like genetic drift, natural selection and many other will act on the population and therefore the gene pool (gene frequency and the genotypic frequency) of a populations remains in equilibrium or constant throughout the generations.
The genotypic frequency in the model is calculated by
P² = genotype of a homozygous dominant trait
q² = genotype of a homozygous recessive trait
2pq = genotype of heterozygous trait.
Thus, P²+2pq+q²=1
In the given question, since the population is in equilibrium that is no evolutionary force is acting, therefore, the genotype frequency remains the same that is the frequency of Aa will remain same that is 2pq even after 100 generations.
Thus, Option-B is the correct answer.
Answer:
The answer is AAG. Hope this helps
Explanation: Mutations are silent. It is called a silent mutation