3 years ago

(x^2-25)^2-(x-5)^2= ?

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

6 0

Answer:

that's the answer

Step-by-step explanation:

hope it help

You might be interested in

What is the length of the conjugate axis?

Lana71 [14]

ANSWER

The length of the conjugate axis is 6 units.

EXPLANATION

The given hyperbola has equation:

$\frac{(x - 1)^{2} }{25} - \frac{ {(y + 3)}^{2} }{9} = 1$

We can rewrite this equation in the form:

$\frac{(x - 1)^{2} }{ {5}^{2} } - \frac{ {(y + 3)}^{2} }{ {3}^{2} } = 1$

We compare this equation to:

$\frac{(x - h)^{2} }{ {a}^{2} } - \frac{ {(y - k)}^{2} }{ {b}^{2} } = 1$

This implies that;

$a = 5$

and

$b = 3$

The length of the conjugate axis of a hyperbola is

$= 2b$

Substitute b=3 to obtain;

$= 2 \times 3$

$= 6$