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3 years ago

Why do non-metals want to form ions?

Chemistry

1 answer:

vova2212 [387]3 years ago

8 0

Answer:

Explanation:

Non-metals want to be stabilized by making the utmost electron shell complete.

Non-metals form ions when they bond with metals to form an ionic bond. But sometimes, they also form ions with non-metals like NH4Cl.

They take away the electrons from the other ion that it bonds with.

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When we mix Cu wire with Silver Nitrate, the following reaction OCCURS.

kherson [118]

Answer:

Yes

2Ag + Cu(No3)2 -----(heat) ----- Cu + 2Agno3

When heat energy is passed through Cu(No3)2 then the reverse reaction will occur

3 0

3 years ago

Granite is formed from magma from earth. which rock is granite

Crank

Granite is an igneous type of rock.

3 0

3 years ago

What does it mean when a reaction has a negative amount of Kj

makvit [3.9K]

Answer:

heat is released in going from reactants to products

Explanation:

hope this helps

3 0

3 years ago

Al2(SO4)3(s) + H2O(l) ---- Al2O3(s) + H2SO4 (aq) calculate enthalpy formation for this reaction. Balance the reaction. Calculate

katen-ka-za [31]

The given chemical equation is:

$Al_{2}(SO_{4})_{3}(aq)+H_{2}O(l)-->Al_{2}O_{3}(aq)+H_{2}SO_{4}(aq)$

On balancing the equation we get,

$Al_{2}(SO_{4})_{3}(aq)+3H_{2}O(l)-->Al_{2}O_{3}(aq)+3H_{2}SO_{4}(aq)$

Calculating enthalpy of formation of this reaction from the standard heats of formation of the products and reactants:

Δ $H_{reaction}^{0}=[H_{f}^{0}(Al_{2}O_{3}(s)) + (3*H_{f}^{0}(H_{2}SO_{4}(aq))] - [H_{f}^{0}(Al_{2}SO_{4}(aq)) + (3*H_{f}^{0}(H_{2}O(l))]$

=[(-1669.8kJ/mol)+ {3* (-909.27 kJ/mol)}]-[(-3442kJ/mol)+{3*(-285.8 kJ/mol)}]

=[(-4397.61kJ/mol)]-[(-4299.4kJ/mol)]

=-98.21kJ/mol

Total enthalpy change when 15 mol of $Al_{2}(SO_{4})_{3}$ reacts will be=

$15 mol Al_{2}(SO_{4})_{3}*\frac{-98.21kJ}{1 molAl_{2}(SO_{4})_{3}} =-1473.15kJ/mol$

4 0

4 years ago

If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed

MaRussiya [10]

The question is incomplete, here is the complete question:

Suppose the reaction is:

$A+2B\rightarrow C$

If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed

<u>Answer:</u> The maximum amount of C produced will be 1 mole

<u>Explanation:</u>

We are given:

Moles of A = 6 moles

Moles of B = 2 moles

For the given chemical reaction:

$A+2B\rightarrow C$

By Stoichiometry of the reaction:

2 moles of B reacts with 1 mole of A

So, 2 moles of B will react with = $\frac{1}{2}\times 2=1$ mole of A

As, As, given amount of A is more than the required amount. So, it is considered as an excess reagent.

Thus, B is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of B produces 1 mole of C

So, 2 moles of given B will produce $=\frac{1}{2}\times 2=1mol$ of C

Hence, the maximum amount of C produced will be 1 mole

3 0

3 years ago