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Fofino [41]
3 years ago
12

Determine the nuclear composition (number of protons and neutrons) of the following isotopes. (a) chromium-52 protons neutrons (

b) selenium-80 protons neutrons (c) molybdenum-98 protons neutrons (d) xenon-132 protons neutrons (e) ytterbium-174 protons neutrons
Chemistry
1 answer:
madreJ [45]3 years ago
6 0

Answer: a) chromium-52 :  protons = 24, neutrons = 28

selenium - 80 :  protons = 34, neutrons = 46

molybdenum-98:  protons = 42, neutrons = 56

xenon-132:  protons = 54, neutrons = 78

ytterbium-174 :  protons = 70, neutrons = 104

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, number of protons = atomic number

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

a) chromium-52 :

Atomic number of Chromium is 24 hence number of protons  = 24

52= 24+ Number of neutrons

Number of neutrons = 28

b) selenium - 80 :

Atomic number of selenium is 34 hence number of protons  = 34

80 =  34 +  Number of neutrons

Number of neutrons = 46

c) molybdenum - 98 :

Atomic number of molybdenum is 42 is  hence number of protons  = 42

98 =  42 +  Number of neutrons

Number of neutrons = 56

d) xenon-132:

Atomic number of xenon is 54 hence number of protons  = 54

132 =  54 +  Number of neutrons

Number of neutrons = 78

e) ytterbium-174:

Atomic number of ytterbium is 70 and  hence number of protons  = 70

174 = 70 +  Number of neutrons

Number of neutrons = 104

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timurjin [86]

Answer:

150.1 mL

Explanation:

Step 1: Given data

  • Density of benzene (ρ): 0.879 g/mL
  • Mass of the sample of benzene (m): 131.9 g
  • Volume of the sample of benzene (V): ?

Step 2: Calculate the volume of the sample of benzene

Density is an intrinsic property. It is equal to the quotient between the mass and the volume of the sample of benzene.

ρ = m/V

V = m/ρ

V = 131.9 g/(0.879 g/mL)

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3 years ago
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Answer: True the dilution formula is a balanced of mole of the solute..

Explanation:

M1V1 = M2V2

When M1= 1.2M, M2= 0.25M V2= 1.4L and V1= ?

Then V1= 0.25*1.4/1.2

= 0.29

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How many grams of sodium Phosphate is needed to prepare 5.0 L of a 2.6M solution ?
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Molarity is the ratio of the moles and the volume. The mass of 2.6 M sodium phosphate solution is 2131.22 gms.

<h3>What is mass?</h3>

Mass is the product of the moles and the molar mass of the substance. It is given as,

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The moles from molar concentration is used to calculate mass as:

Mass = Molarity × volume × molar mass

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Give the concentration of solution which contains 2.5g of sugar dissolved in 50g of water.
meriva

Answer: -

The concentration of solution which contains 2.5 g of sugar dissolved in 50 g of water is 5 % (w/w)

Explanation: -

Amount of sugar = 2.5 g

Mass of water = 50 g

Concentration of sugar = \frac{2.5 g}{50g} x 100

= 5%

Thus the concentration of sugar is 5 % (w/w)

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