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3 years ago

F is between e and g, EF=7 and FG=6. find EG

Mathematics

1 answer:

irina [24]3 years ago

7 0

------- (EF)
------ (FG)
------ + ------- =
6 + 7 =
13

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At a farmers market, Apples are priced at 4lbs for 10$ Raigen needs 8 pounds to make Apple pie. Which equation can be used to fi

Rasek [7]

Answer:

The equation S / 8 = 2.5

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3 years ago

What is the value of x? 3x−8=(8x+4 ----- 2

stepladder [879]

3x-8 = 8x+4

subtract 3x from each side

-8 = 5x+4

subtract 4 from each side

-12 = 5x

divide -12 by 5 to get x

x = -12/5 = -2.4

3 0

2 years ago

A rectangular box with a square base is to be constructed from material that costs $9 per ft2 for the bottom, $5 per ft2 for the

kramer

Answer:

$18.73ft^3$

Step-by-step explanation:

Let

Side of square base=x

Height of rectangular box=y

Area of square base=Area of top= $(side)^2=x^2$

Area of one side face= $l\times b=xy$

Cost of bottom=$9 per square ft

Cost of top=$5 square ft

Cost of sides=$4 per square ft

Total cost=$204

Volume of rectangular box= $V=lbh=x^2y$

Total cost= $9(x^2)+5x^2+4(4xy)=14x^2+16xy$

$204=14x^2+16xy$

$204-14x^2=16xy$

$y=\frac{204-14x^2}{16x}=\frac{102-7x^2}{8x}$

Substitute the values of y

$V(x)=x^2\times \frac{102-7x^2}{8x}=\frac{1}{8}(102x-7x^3)$

Differentiate w.r.t x

$V'(x)=\frac{1}{8}(102-21x^2)=0$

$V'(x)=0$

$\frac{1}{8}(102-21x^2)=0$

$102-21x^2=0$

$102=21x^2$

$x^2=\frac{102}{21}=4.85$

$x=\sqrt{4.85}=2.2$

It takes positive because side length cannot be negative.

Again differentiate w.r. t x

$V''(x)=\frac{1}{8}(-42x)$

Substitute the value

$V''(2.2)=-\frac{42}{8}(2.2)=-11.55$

Hence, the volume of box is maximum at x=2.2 ft

Substitute the value of x

$y=\frac{102-7(2.2)^2}{8(2.2)}=3.87 ft$

Greatest volume of box= $x^2y=(2.2)^2\times 3.87=18.73 ft^3$

5 0

3 years ago

What does the expression 12f + 24 represent? Answers:

PSYCHO15rus [73]

24 more than 12 times a number

7 0

3 years ago

Read 2 more answers

(4y 2 – 5y) + (3y – 7y 2) – (2y 2 + 6y – 5) Simplify.

Elan Coil [88]

Equation at the end of step 1 : (((4•(y2))-5y)+(3y-(7•(y2))))-((2y2+6y)-5) Step 2 :Equation at the end of step 2 : (((4•(y2))-5y)+(3y-7y2))-(2y2+6y-5) Step 3 :Equation at the end of step 3 : ((22y2 - 5y) + (3y - 7y2)) - (2y2 + 6y - 5) Step 4 : Step 5 :Pulling out like terms :

5.1 Pull out like factors :

 -5y2 - 8y + 5 = -1 • (5y2 + 8y - 5)

I hope tht help

4 0

3 years ago