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lyudmila [28]
3 years ago
6

Lori is solving the equation 4x2 + 5x - 6 = 0 using the quadratic formula. Which

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

\frac{ - 5 +   \sqrt{( {5})^{2} } - 4(4)( - 6) }{ 2(4)}

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285 miles

Divide 342 by 6 which will give you 57 and then multiply it by 5 which is 285.
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What shape do you get when the angles of each sides are 80,100,100,80 in that order
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3 years ago
Read 2 more answers
Vat is 2+5+5+5-2
vodka [1.7K]

Answer:

Your answer is 15

Step-by-step explanation:

2+5= 7

7+5= 12

12+5=17

17-2= 15

6 0
3 years ago
Describe and correct the error a student made finding the intercepts of the graph of the line 4x-6y=12
Bingel [31]

Answer:the error is when 6y=12

Step-by-step explanation:

the original problem says 4x-6y=12

so when you get rid of the 4x, it should still be -6y not positive

6 0
3 years ago
For the quadratic function <img src="https://tex.z-dn.net/?f=y%3D%28x%2B4%29%5E2-1" id="TexFormula1" title="y=(x+4)^2-1" alt="y=
xenn [34]

Answer:

y=x^2+8x+15

Intercept form is y= (x+5)(x+3)

vertex is (-4,1)

y intercept is (0,15)

x intercepts are (-5,0) (-3,0)

Step-by-step explanation:

Given quadratic function

y=(x+4)^2-1

To rewrite it in standard form we need to expand (x+4)^2

y=(x+4)(x+4)-1

y=x^2+8x+16-1

y=x^2+8x+15

Intercept form is y=a(x-p)(x-q)

Factor x^2 + 8x + 15

product is 15 and sum is 8, 5*3= 15 and 5+3=8

(x+5)(x+3)

Intercept form is y= (x+5)(x+3)

Vertex form of equation is y=(x-h)^2+k

where (h,k) is the vertex

y=(x+4)^2-1, here h = -4 and k =1 so vertex is (-4,1)

To find y intercept plug in 0 for x

y= (x+5)(x+3)

y= (0+5)(0+3) = 15, so y intercept is (0,15)

to find x intercept plug in 0 for y

y= (x+5)(x+3)

0= (x+5)(x+3),             x+5 =0           and x+3=0

                                   x=-5              and x= -3

So x intercepts are (-5,0) (-3,0)

6 0
3 years ago
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