Ahmad solved 51+4h+2h=27. His work is shown below.

Mathematics

2 answers:

Anna007 [38]3 years ago

7 0

Answer:

Ahmad solution is not correct

h = 1

Step-by-step explanation:

5 + 20h +2h = 27

5+22h = 27

22h = 22

h = 1

dezoksy [38]3 years ago

4 0

$\huge\text{Hey there!}$

$\large\textsf{5(1 + 4h) + 2h = 27}\\\large\textsf{5(1) + 5(4h) + 2h = 27}\\\large\textsf{5 + 20h + 2h = 27}\\\large\large\textsf{5 + 22h = 27}\\\large\textsf{22h + 5 = 27}\\\large\text{SUBTRACT 5 to BOTH SIDES}\\\large\textsf{22h + 5 - 5 = 27 - 5}\\\large\text{CANCEL out: 5 - 5 because that gives you 0}\\\large\text{KEEP: 27 - 5 because that helps us solve for the h-value.}\\\large\textsf{27 - 5 = \bf 22}\\\large\text{DIVIDE 22 to BOTH SIDES}\\\mathsf{\dfrac{22h}{22} = \dfrac{22}{22}}$

$\\\large\text{CANCEL out: }\rm{\dfrac{22}{22}}\large\text{ (the one on the LEFT) because it gives you 1}\\\large\text{KEEP: }\rm{\dfrac{22}{22}}\large\text{ (the one on the RIGHT) because it gives you the result of the h-value}\\\large\text{SIMPLIFY ABOVE AND YOU HAVE YOUR ANSWER OF H}\\\\\\\huge\boxed{\rm{Therefore, \ h = 1}}\huge\checkmark$

$\large\textsf{Therefore, Ahmad is incorrect with his steps because he didnt}\\\large\textsf{5 within the parentheses and didnt combine the like terms for the}\\\large\textsf{2}\mathsf{^{nd}}\large\textsf{ step. }$