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OlgaM077 [116]
3 years ago
14

Can somebody show the work and help me with number 5 please (show the work in the comments)

Mathematics
1 answer:
Arturiano [62]3 years ago
4 0

Um

We need to see the chart

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The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.
Dennis_Churaev [7]

Answer:

Option B is correct.

f(t) = 88(1.025)^t represents the population of the pack of wolves after t years

Step-by-step explanation:

The exponential growth function is given by;

f(t) = a(1+r)^t               ......[1]

where

a represented the initial value

r represents the rate(in decimal)

t represents the time in years

As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.

⇒ a = 88 and  r =2.5% = 0.025.

Substituting these values in equation [1], we have;

f(t) = 88(1+0.025)^t

or

f(t) = 88(1.025)^t

Therefore, the population model of the pack of wolves after t years is given by:  f(t) = 88(1.025)^t





5 0
3 years ago
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