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zimovet [89]
3 years ago
15

How do you draw the unit circle in radians when the denominator is 5?

Mathematics
1 answer:
pochemuha3 years ago
4 0
The radian is with a denominator of 5 is 2.5
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What is the answer to this problem?
Svet_ta [14]

Subtract 180 - 34 = 146

You know ∠BPD adds up to 146°

Since \overrightarrow{PS} bisects ∠BPD, you know that ∠BPC and ∠CPD are equal to each other.

Divide 146 by 2 = 73

m∠CPD = 73°

6 0
3 years ago
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Three roots of a fifth degree polynomial function f(x) are –2, 2, and 4 i. Which statement describes the number and nature of al
bagirrra123 [75]

The correct option is f(x) has three real roots and two imaginary roots.

Given

Three roots of a fifth-degree polynomial function f(x) are –2, 2, and 4 i.

<h3>Complex conjugate</h3>

The complex conjugate of a complex number is the number with an equally real part and an imaginary part equal in magnitude but opposite in sign.

It is given that the roots of the fifth-degree polynomial function are -2, 2, and 4+i.

Since the degree of f(x) is 5, therefore there are 5 roots of the function either real or imaginary.

According to the complex conjugate root theorem, if a+ib is a root of a polynomial function f(x), then a-ib is also a root of the polynomial f(x).

Since 4+i is a root of f(x), so by complex conjugate rot theorem 4-i is also a root of f(x).

From the given data the number of real roots is 2 and the number of 2. The number of complex roots is always an even number, so the last root must be a real number.

Therefore, the correct option is f(x) has three real roots and two imaginary roots.

To know more about imaginary roots click the link given below.

brainly.com/question/1375079

3 0
2 years ago
Please tell me what 1+1 is ??????
Luden [163]
It is 2...hope it helps! 
7 0
3 years ago
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Given the data 14,26,23,19,24,46,15,21: a.what is the outlier in the data? b. What is the mean with the outlier? c. What is the
Olegator [25]
The outlier is the piece of data that does not fit the general data set. In this case, 46 is much higher than all of the other numbers. This is the outlier.
3 0
3 years ago
Simplify 〖3m〗^8 n^3÷(〖3m〗^8 n^3 )^0
vovangra [49]

6561m^{8}n^{3}

3 0
3 years ago
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