The exact value is
<span>sin<span>(arccos<span>(<span>3/4</span>)</span>)</span></span>The equation for cosine is <span>cos<span>(A)</span>=<span>AdjacentHypotenuse</span></span>. The inside trig function is <span>arccos<span>(<span>3/4</span>)</span></span>, which means <span>cos<span>(A)</span>=<span>3/4</span></span>. Comparing <span>cos<span>(A)</span>=<span>AdjacentHypotenuse</span></span> with <span>cos<span>(A)</span>=<span>3/4</span></span>, find <span>Adjacent=3</span> and <span>Hypotenuse=4</span>. Then, using the pythagorean theorem, find <span>Opposite=<span>√7</span></span>.<span>Adjacent=3</span><span>Opposite=<span>√7</span></span><span>Hypotenuse=4</span>Substitute in the known variables for the equation <span>sin<span>(A)</span>=<span>OppositeHypotenuse</span></span>.<span>sin<span>(A)</span>=<span><span>√7</span> over 4</span></span>Simplify.<span><span>√7</span><span> over 4</span></span>
Answer:
False
Step-by-step explanation:
x + 3 < -5
x < -8
-x > -8
x < 8
Both aren't same
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
