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damaskus [11]
2 years ago
12

10+10+10+10+10+5= ? (it equals how many points your getting for answering this)

Mathematics
2 answers:
prohojiy [21]2 years ago
7 0

Answer:

55

Step-by-step explanation:

10+10=20

10+10=20

10+5= 15

20+20=40

40+15=55

therefore that is your answer!!

Rudiy272 years ago
4 0

Answer:

IT EQUALS FIFTY FIVE THANKS

BRAINLIST ???

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A

Step-by-step explanation:

It just is

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Which expression shows a way to find 2,813 x 7?
sergey [27]

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Step-by-step explanation:

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B - Not Rational

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Step-by-step explanation:

3 0
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State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

\:f\left(x-7\right)= \sqrt{3x-23}

From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

7 0
3 years ago
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