Solve for x when x^2 + 5/x = 8
1 answer:
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Answer: The distace between midpoints of AP and QB is .
Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:
AP + PQ + QB = a
According to the question, AP = 2 PQ = 2QB, so:
PQ =
QB =
Substituing:
AP + 2*() = a
2AP = a
AP =
Since the distance is between midpoints of AP and QB:
2QB = AP
QB =
QB =
QB =
MIdpoint is the point that divides the segment in half, so:
<u>Midpoint of AP</u>:
<u>Midpoint of QB</u>:
The distance is:
d =
d =
Answer:
x=2
Step-by-step explanation:
The axis of symmetry can be calculated using the following formula:
In order to use this formula, we need to have the function written in it's polynomial formula:
In order to do so, we have to isolate Y from the excercise's formula.
Then we resolve the square of the binomial knowing that (a+b)^2=a^2+2.a.b+b^2
Now we have that:
As we have now the polynomyal formula, we know that a=-2, b=8 and c=-13. We supplant on the formula and get: