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nlexa [21]
3 years ago
12

Find the lateral area of the cone in terms of pi.

Mathematics
1 answer:
enyata [817]3 years ago
8 0

To find the lateral area of a cone, use this formula:

\pi r\sqrt{h^2+r^2}

where r is the radius (in this case, 11) and h is the height (in this case, 26)

Try plugging the values in. If you need additional help, feel free to ask!

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If Clive was charged $3.92 for a minute 38 call, what is Clive's per minute base rate?
Tanzania [10]
Pretty sure it’s $0.10
8 0
2 years ago
Determine whether the function below is an even function, an odd function, both, or neither.
kari74 [83]
All of the powers of x here are even, so the function f(x) is even.  Note that 19 = 19x^0 = 19(1) = 19

6 0
3 years ago
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
In the diagram below, a right circular cone with a radius of 3 inches has a slant height of 5 inches, and a right cylinder with
Westkost [7]

this is the correct answer

5 0
3 years ago
Malik’s solution to the equation 2/5x-4y=10 , when x=60, is shown below.
zhenek [66]

Answer:

D. Malik substituted 60 for y instead of x.

Step-by-step explanation:

Look closely at the step by step process.

4 0
3 years ago
Read 2 more answers
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