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nlexa [21]
4 years ago
12

Find the lateral area of the cone in terms of pi.

Mathematics
1 answer:
enyata [817]4 years ago
8 0

To find the lateral area of a cone, use this formula:

\pi r\sqrt{h^2+r^2}

where r is the radius (in this case, 11) and h is the height (in this case, 26)

Try plugging the values in. If you need additional help, feel free to ask!

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Multiply and simplify the product. 2i(4 – 5i) select the product. –2i 2i –10 8i 10 8i
Crazy boy [7]

The multiplication of the expressions 2i and (4 – 5i) is 10 + 8i. Then the correct option is D.

<h3>What is multiplication?</h3>

It is also known as the product. If the object n is given to m times then we just simply multiply them.

The expressions are 2i and (4 – 5i).

Then the product of the expression will be given as

2i (4 – 5i)

8i – 10i²

And we know that i² = -1

Then we have

8i – 10 (–1)

10 + 8i

More about the multiplication link is given below.

brainly.com/question/19943359

4 0
2 years ago
A sphere has diameter 28 cm. If the diameter is divided by 2, what is the effect on the surface area?
spayn [35]

Answer:

The surface area is divided by 4.

Step-by-step explanation:

Surface area of a sphere is 4πr².

When the diameter is 28 the radius is 14. So: 4π(14)² = 784π

If you cut the diameter in half you get 14. The radius is now 7.

4π(7)² = 196π.

784/4 = 196 so divided by 4.

4 0
3 years ago
HELP IMMEDIATELY PLEASE, WILL GIVE BRAINLIEST!!!
egoroff_w [7]

Answer:

The slope is -1/3 I think.

5 0
3 years ago
Read 2 more answers
Someone please help me on this question
Rudik [331]
100 + 10x=15x. Subtract 10x from both sides. 100=5x. Divide by 5 on both sides. x=20. So you would need to buy 20 movies. 
7 0
3 years ago
One of the roots of the equation 3x^2+7x−q=0 is −5. Find the other root and q.
statuscvo [17]

Answer: The answer is \textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation:  The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.

Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.

Let the other root of the equation be 'p'. So, we have

p-5=-\dfrac{7}{3}\\\\\\\Rightarrow p=5-\dfrac{7}{3}\\\\\\\Rightarrow p=\dfrac{8}{3},

and

p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.

Thus, the other root is \dfrac{8}{3} and the value of 'q' is 40.

3 0
3 years ago
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