The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
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Answer:
see the attachment
Step-by-step explanation:
1. Two angles that sum to 90° are <em>complementary</em>, whether they are adjacent or not. Angles LMN and NMP are also <em>adjacent</em>.
2. Vertical angles created by two distinct lines are <em>never adjacent</em>. The sides of the angles are created by the same lines, and the angles share a vertex, but there is no ray that is a side common to both angles.
3. Angle GMK is supplementary to angle JMG.
4. Vertical angles are congruent. See question 2.
5. See question 1.
Answer:
Direct variation
Step-by-step explanation:
It's not iverse because the line is curved so it's direct variation
Answer:1.41666666667 or to simplify, 1.416 but the 6 is repeating so draw a bar over the 6.
Step-by-step explanation:
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