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netineya [11]
3 years ago
15

HELP HELP HELP HELP HELP​

Mathematics
1 answer:
Fed [463]3 years ago
3 0
Doing it for points sorry
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-x+26 = 2x-10<br><br>please help!! ​
Leto [7]

Answer:

x=-6

Step-by-step explanation:

3 0
3 years ago
What is the slope of the line that passes through the points (3, 5) and (-1, 5)
Marianna [84]

Answer:

0

Step-by-step explanation:

solve with y2-y1 / x2-x1

5-5 is 0

-1-3 is -4

0/4 is 0

slope is 0

5 0
3 years ago
Helen is preparing candy bags for the children at a party. she has 2 flavors of lollipops, 4 types of candy bars, and 6 flavors
yanalaym [24]
48 total combinations
multiply the 3 numbers together
7 0
4 years ago
Find the slope between the following coordinates. (6,4)&amp;(6,-2)​
Grace [21]

Answer:

slope is undefined

Step-by-step explanation:

calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (6, 4 ) and (x₂, y₂ ) = (6, - 2 )

m = \frac{-2-4}{6-6} = \frac{-6}{0}

division by zero is undefined, therefore the slope of the vertical line is undefined.

4 0
2 years ago
Determine the number of real solutions each quadratic equation has. y = 12x2 - 9x 4 real solution(s) 10x y = -x2 2 real solution
nordsb [41]

All the given equations have 2 real solutions except for equation 4 which has only one real root.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The given quadratic equation

y = 12x^2 - 9x+ 4

where, a = 12, b = -9 and c = 4

x = -b + \sqrt{b^2 - 4ac} /2a

x = -(-9)+ \sqrt{(-9)^2 - 4(12)(4)} /2(12)

x = 1.063 or -0.313

Second Equation

10x +y = -x^2 +2 \\y = x^{2} +10x - 2

where, a = 1, b = 10, c = -2

substitute the values into the equation

x = -b + \sqrt{b^2 - 4ac} /2a

-10 + \sqrt{10^2 - 4(1)(-2)} /2(1)

x = 0.195 or -10.195

Third Equation

4y - 7 = 5x^2 - x +2 +3y

y = 5x^{2} -x -5

where, a = 5, b = -1, c = - 5

x = -b + \sqrt{b^2 - 4ac} /2a

-(-1) + \sqrt{(-1)^2 - 4(5)(-5)} /2(5)

x = 0.905 or -0.55

Fourth Equation

y = (-x +4)^2 \\y = x^{2} -8x +16

where, a = 1, b = -8, c = 16

x = -b + \sqrt{b^2 - 4ac} /2a

x = -(-8) + \sqrt{(-8)^2 - 4(1)(16)} /2(1)

x = 4

Learn more about quadratic equations;

brainly.com/question/13197897

6 0
2 years ago
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