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3 years ago

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Mathematics

1 answer:

Fed [463]3 years ago

3 0

Doing it for points sorry

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How many factors of muliplication does 20 have

amid [387]

Here are some factors of 20!

1x20=20

2x10=20

4x5=20

5x4=20

Therefore there are 4 factors of 20.

4 0

3 years ago

Read 2 more answers

0.9(x+1.4)−2.3+0.1x=1.60.9(x+1.4)−2.3+0.1x=1.6

SIZIF [17.4K]

I assume that the given equation above is 0.9(x+1.4)−2.3+0.1x=1.6 and not 0.9(x+1.4)−2.3+0.1x=1.60.9(x+1.4)−2.3+0.1x=1.6, I think there is a typo error on this. Based on equation I assumed the answer is 2.64.Thank you for posting your question here, I hope my answer helps.

7 0

3 years ago

The solution is u = ?

Tpy6a [65]

Answer:

u = (b/hn)

Step-by-step explanation:

The inverse!!

3 0

2 years ago

1. (k+7)² =289 2. (2s-1)² =225 3. (x-4)² =169 please help me answer these :)

professor190 [17]

$(k+7)^2 =289\\
|k+7|=17\\
k+7=17\vee k+7=-17\\
k=10 \vee k=-24$

$(2s-1)^2 =225\\
|2s-1|=15\\
2s-1=15\vee 2s-1=-15\\
2s=16 \vee 2s=-14\\
s=8 \vee s=-7$

$(x-4)^2 =169\\
|x-4|=13\\
x-4=13 \vee x-4=-13\\
x=17 \vee x=-9$

6 0

3 years ago

Read 2 more answers

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

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2 years ago

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