All categories

2 years ago

. (a + b)2 – (2a – b)

Mathematics

2 answers:

inn [45]2 years ago

3 0

Answer:

(-b) is the answer.

Step-by-step explanation:

2(a-b)-(2a-b)

=2a-2b-2a+b (opening the brackets)

= -b

Hope this helps you buddy. Have a nice day^_^.

If you have doubt then you can ask in comments. I will surely answer.

harina [27]2 years ago

3 0

Answer:

Step-by-step explanation:

=2a +2b-2a+b

=3b

yesyesyrssdfc

You might be interested in

What is all of this Identify ALL sets of parallel and perpendicular lines in this image.

Tamiku [17]

Parallel lines are lines that run side-by-side without touching or intersecting!

Perpendicular lines intersect/cross and can also make 90° angles (those little green boxes in the picture) in their corners!

Sets of parallel lines:

CD and EF

Sets of perpendicular lines:

CD and AB
EF and AB

5 0

2 years ago

Translate The phrase into an algebraic expression.

riadik2000 [5.3K]

10+ 2v .................

5 0

3 years ago

BRAINLIEST PLUS 22 POINTS

Vika [28.1K]

Hi there!

Angles that are complementary add up to 90. We know that in order to find the value of x, we'll need to create an equation. This equation would be (x + 15) + 48 = 90. This is because, together, the two angles must add up to 90.

ANSWER:
D - (x + 15) + 48 = 90

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

6 0

2 years ago

Find the missing side of the triangle. Side LaTeX: cc is the hypotenuse and sides LaTeX: aa and LaTeX: bb are legs. Leave your a

mylen [45]

Answer:

$c = 2\sqrt{5$

Step-by-step explanation:

Given

$a = 2$

$b = 4$

c = hypotenuse

Required

Find c

Using Pythagoras theorem, we have:

$c^2 = a^2 + b^2$

Substitute values for a and b

$c^2 = 2^2 + 4^2$

$c^2 = 4 + 16$

$c^2 = 20$

Take square roots of both sides:

$c = \sqrt{20$

Express 20 as 4 * 5

$c = \sqrt{4 * 5$

Split surd

$c = \sqrt{4} * \sqrt{5$

Take square root of 4

$c = 2 * \sqrt{5$

$c = 2\sqrt{5$

6 0

2 years ago

A plane flies 35 km in the direction n 30° w, then flies 60 km in the direction n 60° e. how far is the plane from its original

Kipish [7]

The distance of plane from the starting point is 69.46 km.

Given that the plane first flies 35 km in the direction N30W and then 60 km in the direction N60E.

We have to find the distance of plane from starting point.

We have to use pythagoras theorem in this which says that the square of hypotenuse is equal to sum of squares of the base and perpendicular.

$H^{2} =P^{2} +B^{2}$