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Sladkaya [172]
3 years ago
13

Look at the image. ( Ill give brainliest to best answer.)

Mathematics
1 answer:
nalin [4]3 years ago
3 0
C. 1 solution hope it helps
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2 1/5 (6/7 - 1 1/14)​
hram777 [196]
If it’s 2(1/5) (6/7-11/14) it equals 0.2867942868 or if it’s 21 divided by five it should equal 30113400109.8 I hope that’s what u needed :( if it’s not im sorry
5 0
3 years ago
What is the distance between (-25, -3) and (1, -3)?
Virty [35]

Answer:

3 1/2

Step-by-step explanation:

HOPE THIS HELPS SORRY FOR CAPS

5 0
3 years ago
The sum of two numers is 52 . The difference of the two numbers is 38 . What are the two numbers? Write the two numbers separate
Ray Of Light [21]
Let the first number be 'x' and the second number is 'y'

Equation 1: x + y = 52
Equation 2: x - y = 38

Rearranging equation 2 to make either x or y the subject
x = 38 + y

Substituting x = 38 + y into equation 1

x + y = 52
(38+y) + y = 52
38 + 2y = 52
2y = 52 - 38
2y = 14
y = 7

Substitute y = 7 into either equation 1 or equation 2 to find x

x + y = 52
x + 7 = 52
x = 52 - 7
x = 45

x = 45
y = 7
8 0
3 years ago
the angle between the length of a rectangle and its diagonal is 30degrees. if the length of the rectangle is 6cm, find the lengt
adell [148]

Answer:

view the picture

Step-by-step explanation:

It is self explanatory

4 0
3 years ago
A computer is used to generate passwords made up of numbers 0 through 9 and lowercase letters. The computer generates 400 passwo
tamaranim1 [39]

The prediction for the number of passwords in which the first character is a vowel is 56 passwords.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials.

Bernoulli trials are those trials which end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

X \sim B(n,p)

The probability that out of n trials, there'd be x successes is given by

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

The expected value and variance of X are:

E(X) = np\\

Given that the characters that can be used are numbers 0 through 9 and lowercase letters. Therefore, a total of 36 different characters are available.

Since we need to know the passwords made with vowels, therefore, the probability of a password in which the first character will be a, e, i, o, u is (5/36).

Now as the computer produces 400 passwords, therefore, the predicted value can be written as,

E = np = 400 \times \dfrac{5}{36} = 55.5556 \approx 56

Hence, the prediction for the number of passwords in which the first character is a vowel is 56 passwords.

Learn more about Binomial Distribution:

brainly.com/question/14565246

#SPJ1

5 0
2 years ago
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