We have a sample of size n = 35, $\bar{x} = 92$ and $s = 5$ . As we want to construct a 95% confidence interval to estimate the value of the true population mean $\mu$ , we should use the pivotal quantity given by $T = \frac{\bar{X}-\mu}{S/\sqrt{n}}$ which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value $t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$ , i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that $P(-2.0322\leq T\leq 2.0322) = 0.95$ because of the simmetry of the t distribution.

7 0

2 years ago

Change the following mixed number to an improper fraction. Reduce if possible.<br><br> 7 81/1000

pogonyaev

The answer is 7081/1000

7 0

2 years ago

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A school custodian waxed a gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?

stealth61 [152]

A school custodian waxed a gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?

If it's 20 feet * 20 feet = to
400 sq.ft

Hope this helps!

6 0

3 years ago