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notsponge [240]
3 years ago
8

WILL GIVE BRAINLEIST The table shows an estimate of the average hourly emissions of sulfur dioxide, SO2, in pounds per megawatt-

hour (In/MWh) from a power plant during the month of January, where 1 represents the hour from 12:00 a.m. to 1-00a.m., and so on. If a statistician decides to use a parabola to model the data, which is the best model?

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:Transcribed image text: on 54 of 54 8 Review Constants 1 Periodic Table On its website, the EPA claims that sulfur dioxide levels have fallen by 85% between 1990 and 2016. Calculate the percent decrease between these two years to determine whether this claim accurate. Express your answer as a percentage. View Available Hint(s) ? ΑΣφ percent decrease % Submit Part B The EPA air quality standard for SO2 is 75 ppb. In what year did the average U.S. SO2 concentration begin to meet this standard? Express your answer as a year, in the format YYYY. View Available Hint(s) first year 75 ppb standard met: Submit Part C 54 of 54 Review Constants 1 Periodic Table Part What is the percent by mass of S in SO2? Express your answer as a percentage to four significant figures. View Available Hint(s) IVO AE ? % Submit Part D A 100 m room with an SO2 concentration of 75 ppb contains about 0.017 g SO2. How many sulfur atoms does it contain? Express your answer to two significant figures. View Available Hint(s) VE] ΑΣφ ? atoms Submit Sulfur dioxide is a pollutant emitted primarily by coal-burning power plants and industrial smelters. Sulfur dioxide in air affects the respiratory system in humans and is the main cause of acid rain. Thanks to the Clean Air Act and its amendments, sulfur dioxide levels in the United States have dramatically fallen over the past 30 years. The graph below shows the mean sulfur dioxide levels from 136 measuring sites in the United States for the period 1990 to 2016. Examine the graph and answer the questions that follow. Sulfur Dioxide Mean Concentration 140 120 100 80 SO, Concentration (ppb) 60 40 20 0 1990 1995 2000 2005 2010 2015 Year 2020

Step-by-step explanation:

Transcribed image text: on 54 of 54 8 Review Constants 1 Periodic Table On its website, the EPA claims that sulfur dioxide levels have fallen by 85% between 1990 and 2016. Calculate the percent decrease between these two years to determine whether this claim accurate. Express your answer as a percentage. View Available Hint(s) ? ΑΣφ percent decrease % Submit Part B The EPA air quality standard for SO2 is 75 ppb. In what year did the average U.S. SO2 concentration begin to meet this standard? Express your answer as a year, in the format YYYY. View Available Hint(s) first year 75 ppb standard met: Submit Part C 54 of 54 Review Constants 1 Periodic Table Part What is the percent by mass of S in SO2? Express your answer as a percentage to four significant figures. View Available Hint(s) IVO AE ? % Submit Part D A 100 m room with an SO2 concentration of 75 ppb contains about 0.017 g SO2. How many sulfur atoms does it contain? Express your answer to two significant figures. View Available Hint(s) VE] ΑΣφ ? atoms Submit Sulfur dioxide is a pollutant emitted primarily by coal-burning power plants and industrial smelters. Sulfur dioxide in air affects the respiratory system in humans and is the main cause of acid rain. Thanks to the Clean Air Act and its amendments, sulfur dioxide levels in the United States have dramatically fallen over the past 30 years. The graph below shows the mean sulfur dioxide levels from 136 measuring sites in the United States for the period 1990 to 2016. Examine the graph and answer the questions that follow. Sulfur Dioxide Mean Concentration 140 120 100 80 SO, Concentration (ppb) 60 40 20 0 1990 1995 2000 2005 2010 2015 Year 2020

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George is 4 times as old as his daughter was 2 years ago. George is 36
fredd [130]

Where is the question?

5 0
4 years ago
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2. Michelle invested $10,000 in an account that earns 8.5% interest that is compounded monthly. Write an exponential model for t
Gala2k [10]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000\\ r=rate\to 8.5\%\to \frac{8.5}{100}\dotfill &0.085\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}

A=10000\left(1+\frac{0.085}{12}\right)^{12\cdot 15}\implies A=10000\left( \frac{2417}{2400} \right)^{180}\implies A\approx 35626.53

8 0
3 years ago
A line has a slope of - 4 and includes the points (6,v) and (3,3). What is the value of v?
labwork [276]

Answer:  v = - 9


Step-by-step explanation:

Since two points on the line are given, we use formula for slope.

Let (a,b) and (c,d) be two points on the line, the slope of the line is given by

m=\frac{d-b}{c-a}.

Hence, using this we have

-4=\frac{3-v}{3-6}

Thus, we have

-4×(-3)=3-v⇒12=3-v⇒12-3=-v⇒v=-9

3 0
4 years ago
Find the area of this trapezoid. Be sure to include the correct unit in your answer. Continue 13 cm 20 cm 8 cm 5 cm 0 0/0 08 cm
kodGreya [7K]

Given:

• Upper Base of trapezoid = 8 cm

,

• Lower base = 20 cm

,

• Length of one leg (also height) = 5 cm

,

• Length of other leg = 13 cm

Let's find the area of the trapezoid.

To find the area of the trapezoid, apply the formula:

A=\frac{a+b}{2}*h

Where:

A is the area

a is the length of upper base = 8 cm

b is the length of the lower base = 20 cm

h is the height = 5 cm

Plug in the values for a, b, and h to find the area, A:

\begin{gathered} A=\frac{8+20}{2}*5 \\  \\ A=\frac{28}{2}*5 \\  \\ A=14*5 \\  \\ A=70\text{ cm}^2 \end{gathered}

Therefore, the area of the trapezoid is 70 cm^2

8 0
1 year ago
What is the slope for (3, 8) and (2, 6). ?
Ivahew [28]

\huge\text{Hey there!}

\huge\textbf{The formula for finding the slope:}

\mathbf{\dfrac{y_2 - y_1}{x_2 - x_1} = slope}

\huge\textbf{Some people understand formula like:}

\mathbf{\dfrac{rise}{run} = slope}

\huge\textbf{Breaking down the question:}

\mathbf{y_2 \rightarrow \boxed{\textbf{6}}}

\mathbf{y_1 \rightarrow \boxed{\textbf{8}}}

\mathbf{x_2 \rightarrow \boxed{\textbf{2}}}

\mathbf{x_1 \rightarrow \boxed{\textbf{3}}}

\huge\textbf{What your equation should look like:}

\mathbf{\dfrac{6 - 8}{2 - 3} = slope}

\huge\textbf{Simplify the equation we came up with:}

\mathbf{\dfrac{6 - 8}{2 - 3} = slope}

\mathbf{\rightarrow \dfrac{-2}{-1} = slope}

\mathbf{\rightarrow -2 \div -1 = slope}

\mathbf{\rightarrow 2 = slope}

\huge\textbf{Thus, the answer should most likely be:}

\huge\boxed{\mathsf{Slope \rightarrow \boxed{\textsf{2}}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>~\frak{Amphite1040:)}</h3>
4 0
2 years ago
Read 2 more answers
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