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Mariana [72]
3 years ago
10

2. Michelle invested $10,000 in an account that earns 8.5% interest that is compounded monthly. Write an exponential model for t

he balance of the account, then determine the amount of money in the account in 15 years.​
Mathematics
1 answer:
Gala2k [10]3 years ago
8 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000\\ r=rate\to 8.5\%\to \frac{8.5}{100}\dotfill &0.085\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}

A=10000\left(1+\frac{0.085}{12}\right)^{12\cdot 15}\implies A=10000\left( \frac{2417}{2400} \right)^{180}\implies A\approx 35626.53

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3 years ago
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Valentin [98]

Answer:

(x-5) (x-2)

Step-by-step explanation:

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4 years ago
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3 years ago
Which means the sum of w and 3.4 is greater than or equal to 10.5?
DochEvi [55]
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5 0
3 years ago
If ( f ∘ g)(x) = x2 - 6x + 8 and g(x) = x - 3, what is f(x)?
DochEvi [55]
\bf \begin{cases}
(f\circ g)(x)=x^2-6x+8\\\\
(f\circ g)(x)=f(~~g(x)~~)\\\\
g(x)=x-3\\
\end{cases}
\\\\\\
\textit{now, one probability is }x^2-1
\\\\\\
f(x)=x^2-1\implies f(~~g(x)~~)=(x-3)^2-1
\\\\\\
f(~~g(x)~~)=(x^2-6x+9)-1\implies f(~~g(x)~~)=x^2-6x+8
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3 years ago
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