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3 years ago

What is an Atom? please help

Chemistry

2 answers:

JulsSmile [24]3 years ago

5 0

Answer:

An atom is the basic building block of matter. Anything that has a mass-- in other words, anything that occupies space--is composed of atoms.

Jlenok [28]3 years ago

3 0

Answer:

An atom is a particle of matter that uniquely defines achemical element.

Explanation:

this might help you

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Why an offspring and its parent share many common traits?

blondinia [14]

Answer:

Explanation: Traits are characteristics, such as its size or height and that comes from parents or other relatives.

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3 years ago

In mutualism _____.

yawa3891 [41]

Answer:

3'' one is correct answer

Explanation:

in mutualism, organisms of different species benefit from cooperation

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3 years ago

Name each subatomic particle, its charge, and its location in an atom.

Tpy6a [65]

Protons: charge +1, have a mass of 1 and are found in the nucleus

Neutrons: charge 0, have a mass of 1 and are found in the nucleus

Electrons: charge -1, have a mass of 1/840 and are found on the outside of the nucleus

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3 years ago

Matter doesn’t have to take up space as long as it has mass TRUE or FALSE

statuscvo [17]

False anything that has mass takes up the space

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4 years ago

Read 2 more answers

ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a

Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{20\text{ min}}$

$k=3.465\times 10^{-2}\text{ min}^{-1}$

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $3.465\times 10^{-2}\text{ min}^{-1}$

t = time passed by the sample = 80 min

a = initial amount of the reactant = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}$

$a-x=0.100M$

Therefore, the concentration of A after 80 min is, 0.100 M

3 0

3 years ago