So knowing the mass of C and H, C=12g and H=1g. We can have 3 C's (3*12=36) and 3 H's (3*1=3) so 36+3 is 39. Plus C3H3 has an empirical formula of CH since C3H3 can be simplified
Answer:
CH₄ will diffuse at faster rate.
Explanation:
According to Graham's law,
The rate of diffusion is inversely proportional to the square root of molar mas of gas.
It is given in question the molar mass of CH₄ is 16 g. Thus the square rot of 16 is.
√16 = 4
The molar mass of SO₂ is 64 g and the square root is,
√64 = 16
As it is stated that diffusion rate is inversely related to the square root of molar mass thus the diffusion rate of SO₂ is lower while methane diffuse faster.
Answer:
0.1077 grams
Explanation:
First we will employ the ideal gas law to determine the number of moles of nitrogen gas.
PV=nRT
P=2 atm
V=20L
R=0.08206*L*atm*mol^-1*K^-1
T=323.15 K
Thus, 2atm*20L=n*0.08206*L*atm*mol^-1*K^-1*323.15K
K, atm, and L cancels out. Thus n=2*20mol/0.08206*323.15=1.5 moles
Lastly, we must convert the number of moles to grams. This can be done by dividing the number of moles by the molar mass of nitrogen gas, which is 14 grams.
1.5/14=0.1077 grams
The answer to this question is HBr
