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White raven [17]
3 years ago
6

Oscar has $1.00 in quarters and dimes. He has 7 coins altogether. How many coins of each kind does he have?

Mathematics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

2 quarters and 5 dimes

Step-by-step explanation:

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BartSMP [9]
24-3x=-27
-24 -24
-3x=-51
— —
-3 -3

X=17
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3 years ago
Is 445,760 divisible by 6?<br><br> HELP ME PLZ!
aivan3 [116]

Answer:

no because a decimal occurs

Step-by-step explanation:

445,760/6 = 74293.3333333

7 0
2 years ago
Read 2 more answers
A machine that fills 12-quart size packages of ice cream runs 8 hours a day, 7 days a week. The machine fills 900 ice cream pack
otez555 [7]

Answer:

Number of ice cream packaged each week = 604,800 Ice cream

Step-by-step explanation:

Given:

One package = 12 ice cream

Per day packing = 8 hour

Number of days work in a week = 7 days

Per hour packing = 900 package

Find:

Number of ice cream packaged each week :

Computation:

⇒ Number of ice cream packaged each week = Number of days work in a week × Per day packing hour × Per hour packing × Per package ice cream

⇒ Number of ice cream packaged each week = 7 × 8 × 900 × 12

⇒ Number of ice cream packaged each week = 604,800 Ice cream

8 0
3 years ago
Choose one of the squares facts from problem 1?
egoroff_w [7]
I think you forgot to put in the image
8 0
3 years ago
Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar
horsena [70]

Answer:

P(A) = \frac{1}{9}

P(B) = \frac{1}{3}

P(C) = \frac{1}{729}

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

P(M) = \frac{1}{3}.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is P(A) = \frac{1}{9}. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}.

C. If the probability that two people have been hired on a specific day of the week is 3(\frac{1}{3}) ^ 2, then the probability that 7 people have been hired on the same day is:

P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}

D. The probability is \frac{1}{729}. This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0
3 years ago
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