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olga_2 [115]
2 years ago
15

How do I turn mix numbers into Improper fraction

Mathematics
2 answers:
grigory [225]2 years ago
6 0
Ok, lets do an example of how to do one.  Lets say you have:

3 12/15.
12 is your numerator and 15 is your denominator (numerator is the number on top, denominator is the number on bottom). If it takes 15/15 pieces to make the number 1, then for the number three, there must be 15 parts for every 1 in the number three, so:

1= 15/15.
           15 15 15
1+1+1= ---+--+---
           15 15 15
so to make 3 12/15 into a improper fraction we must do:

15 15 15 12
---+--+---+---=?
15 15 15 15

remember when adding fractions, you only add the numerators, so:

15 15 15 12  57
---+--+---+---= ---
15 15 15 15  15

57
---   would be your improper fraction.
15

If you need me to explain anything else or you just simply have any questions, feel free to ask me below. Also please mark this answer as the brainliest if it wouldn't be any trouble :).
Daniel [21]2 years ago
4 0
You multiply the whole number and the <span>denominator ( the bottom number in the fraction) and then add the answer of that to the numerator. Hope that helps! :) </span>
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What is the value of -2/5 / 3/4?
Sveta_85 [38]

Answer:

-8/15

Step-by-step explanation:

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2 years ago
A five​-digit number starts with a number between 4​-9 in the first​ position, with no restrictions on the remaining 4 digits. a
Maurinko [17]

Answer:

(a) Pr = 0.3024

(b) Pr = 0.6976

(c) Pr = \frac{^9P_{n-1}}{10^{n-1}}

Step-by-step explanation:

Given

Start = \{5,6,7,8\} i.e. between 4 and 9

n(Start) =4

Digits = 5

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

First\ digit = 4 (i.e. any of the 4 start digits)

Second\ digit = 10\\ (i.e. any of the 10 digits 0 - 9)

Third\ digit = 10 (i.e. any of the 10 digits 0 - 9)

Fourth\ digit = 10 (i.e. any of the 10 digits 0 - 9)

Fifth\ digit = 10 (i.e. any of the 10 digits 0 - 9)

So, the total is:

Total = 4 * 10 * 10 * 10 * 10

Total = 40000

For selection that all digits are different, the selection is:

First\ digit = 4 (i.e. any of the 4 start digits)

Second\ digit = 9 (i.e. any of the remaining 9)

Third\ digit = 8 (i.e. any of the remaining 8)

Fourth\ digit = 7 (i.e. any of the remaining 7)

Fifth\ digit = 6 (i.e. any of the remaining 6)

So:

Selection =4 * 9 * 8 * 7 * 6

Selection =12096

So, the probability is:

Pr = \frac{Selection}{Total}

Pr = \frac{12096}{40000}

Pr = 0.3024

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

P(At\ least\ 1) = 1 - P(None)

So, we have:

Pr= 1 - 0.3024

Pr = 0.6976

Solving (c): An expression to model the probability.

<em>Using (a) as a point of reference, we have;</em>

Pr = \frac{Selection}{Total}

Where

Selection =4 * 9 * 8 * 7 * 6 ---- for selection of 5 i.e. n = 5

Total = 4 * 10 * 10 * 10 * 10

Selection =4 * 9 * 8 * 7 * 6

This can be rewritten as:

Selection = 4 * ^9P_4

4 can be expressed as: 5 - 1

So, we have:

Selection = (5-1) *^9P_{5-1}

Substitute n for 5

Selection = (n-1) *^9P_{n-1}

Selection = (n-1)^9P_{n-1}

Total = 4 * 10 * 10 * 10 * 10

This can be rewritten as:

Total = 4 * 10^4

Total = (5-1) * 10^{5-1}

Total = (n-1) * 10^{n-1}

Total = (n-1) 10^{n-1}

So, the expression is:

Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}

Pr = \frac{^9P_{n-1}}{10^{n-1}}

<em>Where n represents the digit number</em>

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a.

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b.

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c.

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Answer:

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Find:

Number of student bring their lunch

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Number of student bring their lunch = 600 x 10%

Number of student bring their lunch = 60

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