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levacccp [35]
3 years ago
6

Can somebody help me please! I need it done very soon!

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

2,2,3

Step-by-step explanation:

u will get 76 cans for 48 dollars

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HELP ASAPPPP!!!!You are making a picture frame in the craft cabin at summer camp. The frame measures 9 inches by 12
Greeley [361]

Answer:

yes

Step-by-step explanation:

euhm ... did u just asked if a figure with h=9inches and b=12inches is rectangular???

Does it matter what the diagonals are etc?

if the frame has angles of 90° and it has two different lengths then it has to be rectangular. The sides of a square would have the same lengths.

7 0
3 years ago
Write a function rule for the table.
pashok25 [27]

Answer:

it will be the last one bc 18d is on the chart

7 0
2 years ago
Read 2 more answers
Express in numbers six and three hundredths
Afina-wow [57]

Answer:

6.03

Step-by-step explanation:

'6' would be a whole number. When stating decimals, you would say the whole numbers before 'and'.

For example: 5.6 would be 'five and six tenths'. Note that five is before 'and'.

'Three hundredths' would be .03.

Therefore:

"Six and three hundredths" would be '6.03'.

4 0
3 years ago
I need a answer for this
drek231 [11]

Answer:

I think is A but I could be wrong.....But I don't think so because I did the math lol

Step-by-step explanation:

8 0
2 years ago
8. H={all numbers of the form 3n+1, for n a natural number} under multiplication?
poizon [28]

Answer and Step-by-step explanation:

H= {all numbers of the form 3n+1, for n natural number} under multiplication:

Sol: all number of the form 3n+1, for n natural number so, put n=2, 3(2) +1 = 7, which is a natural number. A natural number under multiplication does not form a group because its inverse does not exist.

J= {all number of the form 3n+2, for n natural number} under multiplication:

Sol: all the number of the form 3n+2, n is the natural number does not form a group under multiplication because the identity element does not form in this set, and inverse does not exist.

K= {perfect squares of integers} under addition:

Sol: perfect square of integers under addition does not form a group because the inverse does not exist. For example, for any element x, inverse (-x) does not exist because of a square integer.

L= {perfect squares of integers} under multiplication:

Sol: a set of the perfect square of integers under multiplication is not a set, because it does not have the inverse property

M= {all numbers of the form 2, for n natural number} under addition:

Sol: natural number in the form of 2n, n is a natural number under addition is not a group as it does not have identity property. Identity property, under addition, is zero.

N= {all number of the form 2n, n is natural number} under multiplication:

All number of the form 2n, n is the natural number under multiplication is not a group. Because its inverse does not exist. For example, an element x belongs to a natural number; its inverse (1/x) does not exist in this set.

8 0
3 years ago
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