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STALIN [3.7K]
3 years ago
6

These ones please (:

Computers and Technology
2 answers:
Morgarella [4.7K]3 years ago
6 0
9) Answer: Magnification

10) Answer: True

Hope this helps have a nice day :)
Cerrena [4.2K]3 years ago
5 0

Answer:

D, true and i think d i cant really see sorry

Explanation:

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Kandi recently started working at new job and must become familiar with her computer. If she would like to view what software ha
Kamila [148]

i think its D. All Programs

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Which network could NOT carry commercial traffic?
sattari [20]

ARPANET would not carry it

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______ is a slow process that takes place in nature. (2 points)
netineya [11]

Natural Selection.


♣Amaranthine
6 0
3 years ago
Write programs for two MSP430 boards to do the following:
Rainbow [258]

Answer:

Explanation:

#include "msp430g2553.h"

#define TXLED BIT0

#define RXLED BIT6

#define TXD BIT2

#define RXD BIT1

const char string[] = { "Hello World\r\n" };

unsigned int i; //Counter

int main(void)

{

WDTCTL = WDTPW + WDTHOLD; // Stop WDT

DCOCTL = 0; // Select lowest DCOx and MODx settings

BCSCTL1 = CALBC1_1MHZ; // Set DCO

DCOCTL = CALDCO_1MHZ;

P2DIR |= 0xFF; // All P2.x outputs

P2OUT &= 0x00; // All P2.x reset

P1SEL |= RXD + TXD ; // P1.1 = RXD, P1.2=TXD

P1SEL2 |= RXD + TXD ; // P1.1 = RXD, P1.2=TXD

P1DIR |= RXLED + TXLED;

P1OUT &= 0x00;

UCA0CTL1 |= UCSSEL_2; // SMCLK

UCA0BR0 = 0x08; // 1MHz 115200

UCA0BR1 = 0x00; // 1MHz 115200

UCA0MCTL = UCBRS2 + UCBRS0; // Modulation UCBRSx = 5

UCA0CTL1 &= ~UCSWRST; // **Initialize USCI state machine**

UC0IE |= UCA0RXIE; // Enable USCI_A0 RX interrupt

__bis_SR_register(CPUOFF + GIE); // Enter LPM0 w/ int until Byte RXed

while (1)

{ }

}

#pragma vector=USCIAB0TX_VECTOR

__interrupt void USCI0TX_ISR(void)

{

P1OUT |= TXLED;

UCA0TXBUF = string[i++]; // TX next character

if (i == sizeof string - 1) // TX over?

UC0IE &= ~UCA0TXIE; // Disable USCI_A0 TX interrupt

P1OUT &= ~TXLED; }

#pragma vector=USCIAB0RX_VECTOR

__interrupt void USCI0RX_ISR(void)

{

P1OUT |= RXLED;

if (UCA0RXBUF == 'a') // 'a' received?

{

i = 0;

UC0IE |= UCA0TXIE; // Enable USCI_A0 TX interrupt

UCA0TXBUF = string[i++];

}

P1OUT &= ~RXLED;

}

7 0
4 years ago
Compute the present value of a $5,500 deposit in year 1, and another $5,000 deposit at the end of year 4 using an 8 percent inte
marusya05 [52]

Answer:

Explanation:

Present value is the value in the present of a sum of money, in contrast to some future value it will have when it has been invested at compound interest.

It can be calculated using future value formula below

A = P(1+r/100)^n

where

A = Future value

P = Present value

r = Rate of interest

n = time period

Present Value = Value at Year 1 + Value at Year 4

Calculating Value at Year 1

A = $5,500

r = 8%

n = 1

From A = P(1+r/100)^n ; Make P the subject of formula

P = A ÷ (1 + r/100)^n

Substitute in values

P = $5,500 ÷ (1 + 8/100)^1

P = $5,500 ÷ (1 + 0.08)

P = $5,500/1.08

P = $5092.5925926

P = $5092.59 ----

Present Value at Year 1 = $5092.59

Calculating Value at Year 4

A = $5,000

r = 8%

n = 1

From A = P(1+r/100)^n ; Make P the subject of formula

P = A ÷ (1 + r/100)^n

Substitute in values

P = $5,000 ÷ (1 + 8/100)⁴

P = $5,000 ÷ (1 + 0.08)⁴

P = $5,000/1.08⁴

P = $3675.149263982267

P = $3675.15 ----

Present Value at Year 4 = $3675.15

Present Value = Value at Year 1 + Value at Year 4

Substitute each value

Present Value = $5092.59 + $3675.15

Present Value = $8,767.74

8 0
3 years ago
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