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Yakvenalex [24]

3 years ago

11

Please answer fast I need this a lot

1 answer:

algol [13]3 years ago

4 0

Answer:

C. O.875

Step-by-step explanation:

7/8 = 0.875

Hope This Helps :)

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Choose the property of addition that justifies the equation<br><br> 9+2=2+9

Alenkasestr [34]

Answer:

Communitive Property

Step-by-step explanation:

Communitive property is when you switch up numbers when you multiply and add but it's still the same.

4 0

3 years ago

Find the simple interest on a $340 loan at a 15% annual interest rate for 1<br> year

Crank

Answer:

$51.

Step-by-step explanation:

Interest I = PRT/100 where P = amount of the loan , R = rate and T = the times in years.

I = 340 * 15 * 1 / 100

= 5100/100

= $51.

4 0

3 years ago

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Do you know how to bake a muffan

soldier1979 [14.2K]

Answer:

yea by using a resipe

Step-by-step explanation:

4 0

3 years ago

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A bird is gliding at 40 meters per minute. How long, in minutes, will it take the bird to travel 160 meters?

adoni [48]

Answer:

<u>4 minutes</u>

Step-by-step explanation:

40=1 min

40=2 min

40=3 min

40=<u>4</u> min

40x4 or 40+40+40+40 is <u>160</u>

6 0

2 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers