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2 years ago

HELPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

zimovet [89]2 years ago

5 0

Answer:

3x+2°=65° (vert opp angles)

3x=65°-2°

=63°

x=63÷3

=21

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The radius of a cylindrical construction pipe is 1.5ft. If the pipe is 18ft long, what is its volume? Use the value 3.14 for π ,

olya-2409 [2.1K]

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=1.5\\
h=18
\end{cases}\implies V=\pi \cdot 1.5^2\cdot 18$

3 0

3 years ago

Help me please this is for a math test. <br> Thank you

zubka84 [21]

Answer:

x + 3y = -12

Step-by-step explanation:

y = mx + b

m is the slope = rise / run:

rise = 1

run = 3

the line is downhill so its negative

m = - 1 / 3

b is the y intercept which is when the line cross over the y axis: - 4

y = - 1/3x - 4

multiply both sides by 3

3y = -1x - 12

add x to both sides

x + 3y = -12

7 0

1 year ago

Simplify and write as a decimal.

oksian1 [2.3K]

11.9

i just got it right on a quiz so yeah

6 0

3 years ago

How do I do this?<br>*Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

7 0

2 years ago

A jar of salsa costs $0.95. Neha bought 9 jars of salsa. How much did Neha spend in all? <br><br> $

olga2289 [7]

Answer:

$8.55

Step-by-step explanation:

$0.95 x 9 jars = $8.55

For every jar Neha buys, she spends $0.95, and buying 9 jars in total, she pays $8.55 in total.

5 0

3 years ago

Read 2 more answers