Answer:
My answer is C
Step-by-step explanation:
I know how to use a graph kind of but I have trouble of calculating and stuff like that.
Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
60°, arms 6
Step-by-step explanation:
let the total arms = n
total generated angles in a regular polygon is = (n-2)×180
now,
(n-2)×180 = 120 n
or, 180n - 360 =120n
or, 60n = 360
or, n = 6
Y=mx+b
m=slope
b=y intercept
we are given (3,-1)
one solution is x=3 and y=-1 or
when x=3 then y=-1
also slope=2
so
y=2x+b
subsitue 3 for x and -1 for y and solve for b
-1=2(3)+b
-1=6+b
subtract 6
-7=b
y=2x-7 is equation
answer is number 4
