Tarana mailed 20 greetings cards. 9 of them were mailed to USA. What percentage of the cards were mailed to USA?

Mathematics

1 answer:

Elza [17]2 years ago

7 0

Answer:

45%

Step-by-step explanation:

9/20=0.45 (Divide it first), 45/100=45% (45/100 because 100 makes 1 whole -all 20 cards-)

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Write down the value of 5 in the following numbers.

Sliva [168]

50 tens
5000 thousands
50000 ten thousand
50 tens
5
Hope this helps

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3 years ago

Quadratic Word Problems

Anit [1.1K]

4. Let the numbers be x - 2, x, and x + 2, where x is an odd number.
2(x² - 4) - 4x = (x + 2)² + 21
2x² - 8 - 4x = x² + 4x + 4 + 21
2x² - 4x - 8 = x² + 4x + 25
x² - 8x - 33 = 0
(x - 11)(x + 3) = 0

x = 11, or -3
When x = 11, x - 2 = 9, x + 2 = 13

When x = -3, x - 2 = -5, x + 2 = -1

Explanation: You are on the right track. However, rather than having three unknown variables, try to reduce your working out to one unknown variable. Since you know they are consecutive odd numbers, you can simply let x be the middle term and the other two be + and - 2, provided x is an odd number.

That will reduce your variable issues, and helps as the first and third provide a difference of two squares, and this works out very nicely.

Q5: is essentially the same process. Let your variables be something in the form of one unknown variable, and you should be okay from there. Let me know if you're stuck.

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2 years ago

Indicate below whether the equation in the box is true or false 1/6 = to 6/12

Vitek1552 [10]

Answer: 1/6 is not equal to 6/12 because 6/12 is 1/2 and 1/6 is less

Step-by-step explanation:

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3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

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2 years ago

Solve for a: b − 2a = c

vlada-n [284]

Answer:

$a=-\frac{c-b}{2}$