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2 years ago

I need help please asp !!!

Mathematics

1 answer:

Marina86 [1]2 years ago

4 0

Answer:

They are all equal and identical in form; coinciding exactly when superimposed.

Step-by-step explanation:

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How would you calculate 7x + 1=68 with only one variable? (Working please)

Tanya [424]

Well if you're solving for x this would be rather simple. 7x +1=68 , then you'd minus 1 from both sides. 7x = 67 then divide 67 by 7. The answer isn't a whole number so x would either be 67/7 or 9.57.. etc.

6 0

3 years ago

Tim installs 50 square feet on his floor in 45 minutes. At this rate, how long does it take him to install 495 square feet?

Katena32 [7]

Answer:

445.5 minutes

or 7 hours 25 minutes 30 seconds

Step-by-step explanation:

We can use ratio's to solve

50 ft^2 495 ft^2

-------------- = ------------

45 minutes x minutes

Using cross products

50x = 45*495

50x=22275

Divide each side by 50

50x/50 = 22275/50

x =445.5

445.5 minutes

If we want to convert to hours and minutes, divide by 60

7 hours is 420 minutes

445.5 -420 = 25.5

7 hours 25 minutes

.5 minutes is 30 seconds

7 hours 25 minutes 30 seconds

6 0

2 years ago

using strips of paper or straws construct a triangle that has lengths of 3 in 3 in and 2 in include a picture of this constructi

koban [17]

Answer:

the triangle is an isosceles triangle.

Step-by-step explanation:

8 0

2 years ago

A certain test preparation course is designed to help students improve their scores on the GRE exam. A mock exam is given at the

Westkost [7]

Answer:

(0.25 ; 21.75)

8.7 (1 decimal place)

Step-by-step explanation:

Net change in scores : X = 6,14,12,23,0

Sample mean, xbar = (6 + 14 + 12 + 23 + 0) /5 = 55 /5 = 11

Sample standard deviation, s = 8.66 ( from calculator)

Sample standard deviation = 8.7( 1 decimal place)

Sample size, n = 5

The 95% confidence interval; we use t, because n is small

Tcritical at 95%, df = 4 - 1 = 3 ; Tcritical = 2.776

Xbar ± standard Error

Standard Error = Tcritical * s/√n

Standard Error = 2.776 * 8.66/√5

Standard Error = 10.751086 = 10.75

Lower boundary = (11 - 10.75) = 0.25

Upper boundary = (11 + 10.75) = 21.75

(0.25 ; 21.75)

The

8 0

2 years ago

Evaluate the integral

Kruka [31]

Hello, please consider the following.

$\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}$

And we can recognise the same integral, so.

$\displaystyle (25-1)\int\limits^x {5sin(5t)sin(t)} \, dt= +5sin(5x)cos(x)-25cos(5x)sin(x)$

And then,

$\displaystyle \Large \boxed{\sf \bf\int\limits^x {5sin(5t)sin(t)} \, dt=\dfrac{5sin(5x)cos(x)-25cos(5x)sin(x)}{24}+C}$

Thanks

3 0

2 years ago