Question

​​someone pls help meeeee!!!!!!​​

Answer 1

Step-by-step explanation:

y = y

x - 2 = 2x - 3 - 3x²

3x² + x - 2x = - 3 + 2

3x² - x = - 1

.

a = 3, b = -1, c = 0

.

$\sf{x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a} }$

$\sf{x = \frac{- (-1) \pm \sqrt{-1^{2} - 4 (0)} }{2(3)} }$

$\sf{x = \frac{ 1 \pm \sqrt{1 - 0} }{6} }$

$\sf{x = \frac{ 1 \pm \sqrt{1} }{6} }$

$\sf{x = \frac{ 1 + 1 }{6} }$

$\sf{x = \frac{ 2 }{6} }$

$\sf{x = \frac{ 1 }{3} }$

.

Substitution :

y = x - 2

y = ⅓ - 2

y = ⅓ - 6/3

y = - 5/3

y = - 1 ⅔

.